Moles of Hydrogen present: 100 / 2 = 50 moles
Moles of Nitrogen present: 200 / 28 = 7.14 moles
Hydrogen required by given amount of nitrogen = 7.14 x 3 = 21.42 moles
Hydrogen is excess so we will calculate the Ammonia produced using Nitrogen.
Molar ratio of Nitrogen : Ammonia = 1 : 2
Moles of ammonia = 7.14 x 2 = 14.28 moles
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Correct Answer: <u>Option B i.e. 0.82 M
</u>
Reason:
<em>Given:</em> number of moles of BaCl2 = 0.98, Volume of solution = 1.2 l
Molarity of solution = </span>

<span>
= </span>

<span>
= 0.82 M
Thus, molarity of the solution is 0.82 M</span>