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inn [45]
2 years ago
7

CCC Matter and Energy The dashed curve shows

Chemistry
1 answer:
Bogdan [553]2 years ago
7 0

The amount of absorption force is not same at all time and at all where .

It has difference at different time periods

So during those the curve goes up and down and repeat this flow

So there are dips

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Which of the following are examples of types of mixtures?
aev [14]
I think it would be homogeneous and heterogeneous
6 0
3 years ago
What is the value of delta Hrxn for this equation:
Ratling [72]

Answer:

The ΔHrxn for the above equation = 179 kJ/mol

Explanation:

The reaction bond enthalpies are for the reactant;

3 × N-H = 3 × 390 = 1,170 kJ/mol

2 × O=O = 2 × 502 = 1004 kJ/mol

The reaction bond enthalpies are for the product;

3 × N-O = 3 × 201 = 603 kJ/mol

3 × O-H = 3 × 464 = 1,392 kJ/mol

The ΔHrxn for the above equation is therefore;

ΔHrxn = 1,170 + 1,004 - (603 + 1,392) = 179 kJ/mol

6 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLEST! what is life about?
erma4kov [3.2K]

Answer:

To live for God.

Explanation:

We are Gods creation. We are here to live for the Lord, to do love& to help save each other so when time comes we will be forever blessed.

7 0
3 years ago
Read 2 more answers
What volume (L) of 0.250 M HNO3 is required to neutralize a solution prepared by dissolving 17.5 g of NaOH in 350 mL of water ?
IRINA_888 [86]
<h3>Answer:</h3>

1.75 L HNO₃

<h3>Explanation:</h3>

We are given;

Molarity of HNO₃ as 0.250 M

Mass of NaOH as 17.5 g

Volume of NaOH = 350 mL

We are required to calculate the volume of 0.250 M

We are going to first write the balanced reaction:

NaOH(aq) + HNO₃(aq) → NaNO₃(aq) + H₂O(l)

Then, we calculate the number of moles of NaOH

Moles = Mass ÷ Molar mass

Molar mass of NaOH = 39.997 g/mol

          = 17.5 g ÷ 39.997 g/mol

          = 0.4375 moles

We can now calculate the number of moles of HNO₃ using the mole ratio from the equation;

Mole ratio of NaOH to HNO₃ is 1 : 1

Therefore, if moles of NaOH are 0.4375 moles then;

Moles of HNO₃ will also be 0.4375 moles

We can now calculate the volume of HNO₃

Morality = Number of moles ÷ Volume

Thus;

Volume = Number of moles ÷ Molarity

             = 0.4375 moles ÷ 0.250 M

             = 1.75 L

Therefore, the volume of HNO₃ is 1.75 L

5 0
3 years ago
Determine the maximum amount of Fe that was produced during the experiment. Explain how you determined this amount.
dsp73

Answer:

5 moles of Fe

Explanation:

The equation of the reaction is;

2 Al(s) + Fe 2O 3(s) --> 2Fe (s) + Al 2O 3 (s)

Now;

1 mole of Fe2O3 require 2 moles of Al

3 moles of Fe2O3 requires 3 × 2/1 = 6 moles of Al

Hence Al is the limiting reactant.

If 2 moles of Al yields 2 moles of Fe

5 moles of Al yields 5 × 2/2 = 5 moles of Fe

5 0
2 years ago
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