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ElenaW [278]
3 years ago
6

According to the relationship between torque and angular acceleration, what happens when you have more torque (given a constant

rotational inertia)?
A. The angular acceleration increases.
B. The angular acceleration decreases.
C. The angular acceleration stays constant.
D. Not enough information to know.
Physics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

The angular acceleration increases.

Explanation:

The relationship between the torque and angular acceleration is :

\tau=I\times \alpha

Where

I is the moment of inertia

\alpha is the angular acceleration

We can see that the torque is directly proportional to the angular acceleration. So, when we have more torque it means angular acceleration increases. Hence, the correct option is (A).

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You need to find the mass of water in the pool.
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3 years ago
Three parachutists have the following masses: A: 50 kg, B: 40 kg, C: 75 kg Which one has the greatest terminal velocity?
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Answer:

A: 50 kg

Explanation:

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3 years ago
Four particles are in a 2-d plane with masses, x- and y- positions, and x- and y- velocities as given in the table below: what i
Arte-miy333 [17]
I attached the picture of the missing table.
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
R=\frac{1}{M}\sum_{i=1}^{n=i}m_ir_i
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
R_x=\frac{1}{M}\sum_{i=1}^{n=i}m_ix_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
R_x=0.96m
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
R_y=\frac{1}{M}\sum_{i=1}^{n=i}m_iy_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
R_y=-0.84m
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
v_x=\frac{\sum_{i=1}^{n=i}m_iv_x_i}{M}
v_y=\frac{\sum_{i=1}^{n=i}m_iv_y_i}{M}
Total velocity is:
v=\sqrt{v_x^2+v_y^2}
Once we calculate velocities we get:
v_x=-1.08\frac{m}{s}\\ v_y=-0.03\frac{m}{s}\\ v=\sqrt{(-1.08)^2+(-0.03)^2}=1.08\frac{m}{s}
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing

3 0
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Moving a charged object against an electrical force causes it to
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Decelerate

<u>Explanation:</u>

If a charged object is moving against an electric force, the electric force would cause the charged object to decelerate. Rate of deceleration would depend on the amount of the charge the object posses and amount of the opposing electric force.

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5 0
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