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4 years ago

Define momentum in terms of football.

1 answer:

7 0

The law of conservation of momentum basically means that energy is always conserved and never lost when a collision happens.

Using the formula p=mv ...
Player A would have a momentum of 220 N•S
Player B would have a momentum of 0 because he is not moving

After the collision, the total momentum is still 220 N•S because energy is never lost, but now player A is at 0 and player B took his momentum. Think about it this way, if you bumped into something that wasn’t moving, it would fall and you most likely wouldn’t keep moving.

Elastic collisions are where the objects bounce each other and in inelastic collisions they stick together. I don’t watch much football but if you do this should make sense.
If the players fall down together (they tackle each other and fall? I think) it should be inelastic.

Sorry if this was long and confusing but I really hope this helps! ☺️

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What happens to an object as its kinetic energy increases?

Reptile [31]

Its moves more, If an object moves it has a kinetic enegy

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3 years ago

An ideal parallel-plate capacitor having circular plates of diameter D that are a distance d apart stores energy U when it is co

Stella [2.4K]

Answer: $\sqrt{3}D$

Explanation:

Given

Diameter of Plates is D

distance between Plates is d

Energy Stored in the Plates is U

Suppose fixed Potential is V

Energy is given by

$U=\frac{1}{2}CV^2$

where C=capacitance

$C=\frac{\epsilon A}{d}$

where A=area of Plates

$A=\frac{\pi D^2}{4}$

Thus $C=\frac{\epsilon \cdot \pi \cdot D^2}{4d}$

Keeping all other factors as same

$U\propto D^2----1$

For triple the Energy

$3U\propto (D')^2-----2$

divide 1 and 2 we get

$\frac{U}{3U}=\frac{D^2}{D'^2}$

$D'=\sqrt{3}D$

Thus the diameter should be change to $\sqrt{3}$ times of original value

3 0

3 years ago

In a fluorescent tube of diameter 3 cm, 3 1018 electrons and 0.75 1018 positive ions (with a charge of e) flow through a cross-s

Vinil7 [7]

Answer:

The current in the tube is 0.601 A

Explanation:

Given;

diameter of the fluorescent, d = 3 cm

negative charge flowing in the fluorescent tube, -e = 3 x 10¹⁸ electrons/second

positive charge flowing in the fluorescent tube, +e = 0.75 x 10¹⁸ electrons/ second

The current in the fluorescent tube is due to presence of positive and negative charges to create neutrality in the conductor (fluorescent tube).

Q = It

I = Q/t

where;

I is current in Ampere (A)

Q is charge in Coulombs (C)

t is time is seconds (s)

1 e = 1.602 x 10⁻¹⁹ C

3 x 10¹⁸ e/ s = ?

= (3 x 10¹⁸ e/s x 1.602 x 10⁻¹⁹ C) / 1e

= 0.4806 C/s

negative charge per second (Q/t) = 0.4806 C/s

positive charge per second (Q/t) = (0.75 x 10¹⁸ e/s x 1.602 x 10⁻¹⁹ C) / 1e

positive charge per second (Q/t) = 0.12015 C/s

Total charge per second in the tube, Q / t = (0.4806 C/s + 0.12015 C/s)

I = 0.601 A

Therefore, the current in the tube is 0.601 A

7 0

3 years ago

7. You are floating motionless on a rubber raft in thelmiddle of a pool. A friend forms a wave by slapping the water

german

Answer:

Yes if it continues in that direction.

Explanation:

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4 years ago

what is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?

timurjin [86]

The initial velocity of go-kart is 2.5 m/s.

<u>Explanation:</u>

Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.

In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.

As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.

$Acceleration = \frac{Final velocity -Initial velocity}{Time}$

Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,

$-0.5=\frac{-\text {Initial velocity}}{5}$

Initial velocity = 0.5 × 5 = 2.5 m/s.

So the initial velocity of go-kart is 2.5 m/s.

8 0

3 years ago