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Ymorist [56]
2 years ago
11

A girl throws a tennis ball upward with an initial velocity of 4 m/s. What is the maximum displacement of the ball?

Physics
1 answer:
Jobisdone [24]2 years ago
8 0

Answer:

0.82 m

Explanation:

The ball is in free fall - uniform accelerated motion with constant acceleration downward, a=g=-9.8 m/s^2 (acceleration of gravity). So we can use the following suvat equation to solve the problem:

v^2-u^2=2as

where

v is the final velocity

u = 4 m/s is the initial velocity

a is the acceleration

s is the displacement

At the maximum displacement, v = 0 (the velocity becomes zero). Substituting and solving for s, we find:

s=-\frac{u^2}{2a}=-\frac{4^2}{2(-9.8)}=0.82 m

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A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp
dusya [7]

from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"

here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

Answer:

(A) 26 m/s

(B) 32.4 m

(C) v = 15.4 m/s

Explanation:

initial speed (u) = 6.4 m/s

acceleration due to gravity (a) = 9.9 m/s^[2}

time (t) = 2 s

(A)   What is its speed after falling for 2.00s?

  from the equation of motion v = u + at we can get the speed

v = 6.4 + (9.8 x 2) = 26 m/s

(B) How far does it fall in 2.00s?

  from the equation of motion s=ut+0.5at^{2} we can get the distance covered

s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)

s = 12.8 + 19.6 = 32.4 m

c) What is the magnitude of its velocity after falling 10.0m?

from the equation of motion below we can get the velocity

v^{2} = u^{2} + 2as\\v^{2} = 6.4^{2} + (2x9.8x10)\\V^{2} = 236.96\\v = \sqrt{236.96}

v = 15.4 m/s

7 0
2 years ago
The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2. Compute the wavelength of this line for l H a
irina1246 [14]

Answer:

\lambda=550\ nm

Explanation:

The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2 i.e. n_i=3 and n_f=2

The wavelength of Hi line of the Balmer series is given by :

\dfrac{1}{\lambda}=R(\dfrac{1}{n_f}-\dfrac{1}{n_i})

\dfrac{1}{\lambda}=1.09\times 10^7\times (\dfrac{1}{2}-\dfrac{1}{3})

\lambda=5.50\times 10^{-7}\ m

\lambda=550\ nm

So, the wavelength for this line is 550 nm. Hence, this is the required solution.

6 0
2 years ago
6. Dan wants to create acceleration. He
kiruha [24]

d. Maintain constant velocity

Explanation:

A constant velocity leads to no acceleration.

Acceleration is defined as the change in velocity with time:

  Acceleration = \frac{change in velocity}{time taken}

If there is no change in velocity i.e constant velocity.

At constant velocity, the change in velocity is 0.

 If we put zero in the equation above, we will obtain an acceleration value of 0.

Learn more:

Acceleration brainly.com/question/3820012

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3 years ago
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Answer: I believe is A

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Explanation:

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