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Verdich [7]
3 years ago
10

Which type of chemical reaction occurs in Ca + Cl2 ->CaCl2?

Chemistry
2 answers:
Mars2501 [29]3 years ago
7 0
Ca + Cl2 ->CaCl2 <span>synthesis  (check your chemistry lesson)</span>
oksano4ka [1.4K]3 years ago
5 0
A. Synthesis is the correct answer
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Because oxygen is more electronegative than hydrogen, the water molecule is
lapo4ka [179]
The water molecule<span> has two </span>hydrogen<span> atoms joined to one </span>oxygen<span> atom by single covalent bonds. </span>Because oxygen is more electronegative than hydrogen<span>, the electrons of the covalent bond spend </span>more <span>time closer to the </span>oxygen<span> then </span>hydrogen<span> which creates a polar covalent bond. Hope this answers your question. Have a great day!</span>
7 0
3 years ago
What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

3 0
3 years ago
What do the colors of light combine to make _______________ light.
Karo-lina-s [1.5K]

the answer is dure light I'm not sure of this answer ,but it might be to go with .

8 0
2 years ago
Which of the following statements about trends in solubility is accurate?
Kipish [7]

"The solubility of gases decreases as temperature rises" statements about trends in solubility is accurate.

<u>Option: D</u>

<u>Explanation:</u>

A substance's solubility is the quantity of that component that is needed at a defined degree of temperature to produce a saturated solution in any set quantity of solvent. Some compounds like hydrochloric acid, ammonia, etc  have solubility that reduces with rising temperature. They are both standard-pressure gases.

When heating a solvent with a gas absorbed in it, both the solvent and the solute spike in the kinetic energy.When the gaseous solute's kinetic energy rises, the molecules have a higher propensity to overcome the solvent molecules' connection and migrate to the gas phase. Thus, a gas's solubility reduces with rising temperature.

4 0
3 years ago
Part V Write the (a) half reaction of oxidation, (b) half reaction of reduction, &amp; (c) the balanced redox reaction for all o
Eduardwww [97]

Answer:

Explanation:

a. Oxidation : 2O + 4e^- ------> 2O^2-

b. Reduction: 2Sr - 4e- -------> Sr^2+

c. Balanced redox reaction

2Sr + O2 ------------> 2Sr O

Oxidation and reduction can be defined by various means, addition of oxygen, removal of hydrogen, removal of electrons. For this reaction, this definition is used, oxidation is the loss of electrons while reduction is the gaining of electrons.

In (a) oxidation half reaction, the valency of oxygen is zero and then moves into lossing two electrons resulting into -2 valency.

In (b) reduction half reaction, the valency of Sr is zero and gains electrons resulting into valency of 2.

In the overall redox reaction, Sr and O2 with valency of 0 each reacts together and form SrO with valency of 2 and -2 respectively, which gives 0 and then balances the equation.

8 0
3 years ago
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