Answer:Amplitude in a longitudinal wave
Explanation:Wave amplitude of a longitudinal wave is the distance between particles of the medium where it is compressed by the wave. Wave amplitude is determined by the energy of the disturbance that causes the wave. A wave caused by a disturbance with more energy has greater amplitude.
Answer:
<h2>15 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
![a = \frac{f}{m} \\](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bf%7D%7Bm%7D%20%20%5C%5C%20)
f is the force
m is the mass
From the question we have
![a = \frac{300000}{20000} = \frac{30}{2} \\](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7B300000%7D%7B20000%7D%20%20%3D%20%20%5Cfrac%7B30%7D%7B2%7D%20%20%5C%5C%20)
We have the final answer as
<h3>15 m/s²</h3>
Hope this helps you
Answer:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.03901 mol/liter
- [Cl₂O] = 0.02351 mol/liter
Explanation:
<u />
<u>1. Chemical reaction:</u>
![H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)](https://tex.z-dn.net/?f=H_2O%28g%29%2BCl_2O%28g%29%5Crightleftharpoons%202%20HOCl%28g%29)
<u>2. Initial concentrations:</u>
i) 1.3 g H₂O
- Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol
- Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter
ii) 2.2 g Cl₂O
- Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol
- Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter
<u>3. ICE (Initial, Change, Equilibrium) table</u>
![H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)](https://tex.z-dn.net/?f=H_2O%28g%29%2BCl_2O%28g%29%5Crightleftharpoons%202%20HOCl%28g%29)
I 0.0481 0.0326 0
C -x -x +x
E 0.0481-x 0.0326-x x
<u />
<u>4. Equilibrium expression</u>
![K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}](https://tex.z-dn.net/?f=K_c%3D%5Cdfrac%7B%5BHOCl%5D%5E2%7D%7B%5BH_2O%5D.%5BCl_2O%5D%7D)
![0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}](https://tex.z-dn.net/?f=0.09%3D%5Cdfrac%7Bx%5E2%7D%7B%280.0481-x%29%280.0326-x%29%7D)
<u />
<u>5. Solve:</u>
![x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0](https://tex.z-dn.net/?f=x%5E2%3D0.09%28x-0.0481%29%28x-0.0326%29%5C%5C%5C%5C0.91x%5E2%2B0.007263x-0.000141125%3D0)
Use the quadatic formula:
![x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-0.007263%5Cpm%20%5Csqrt%7B%280.007263%29%5E2-4%280.91%29%28-0.000141125%29%7D%7D%7B2%280.91%29%7D)
The positive result is x = 0.00909
Thus the concentrations are:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter
- [Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter
Answer:
The simplified mechanism and products are on the picture.
Explanation:
If we have the symmetrical alkene the addition of mercury and OH group is not regioselective but when we have more donors for one of Carbons in alkene then the OH group will go there.
Answer:
They have the same mass but different electrical charges.
Explanation:
Protons have a positive charge while neutrons have a neutral charge. Although they have different charges, they have the same amount of mass.