<u>Answer:</u> Copper is getting oxidized and is a reducing agent. Silver is getting reduced and is oxidizing agent.
<u>Explanation:</u>
Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.
Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.
For the given chemical reaction:

The half reactions for the above reaction are:
<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u> 
From the above reactions, copper is loosing its electrons. Thus, it is getting oxidized and is considered as a reducing agent.
Silver is gaining electrons and thus is getting reduced and is considered as an oxidizing agent.
Answer:
Molecularity of the rate determining step = 2
Explanation:
Step 1 (slow): H₂O₂ + I⁻ -----> H₂O + OI⁻
Step 2 (fast): H₂O₂ + OI⁻ -----> H₂O + O₂ + I⁻
The rate determining step in a reaction mechanism is also considered as slowest step.
Slowest step is also considered its highest activation energy in energy profile diagram.
In this case intermediate (IO⁻) is formed.
Step 1 considered as a slowest step.
So, Rate = K [H₂O₂][I⁻]
Molecularity = 2
i think its a right tringle