3- For given three vectors a, b and c, c = a x b, then the vector c is:

Tire inflation is very important to the safe and economical operation of any vehicle. Technician A says that the tire pressure s

sergejj [24]

Answer:

Both technicians A and B are correct, the information on how to fill the car tires can be located on the tire and on the placard on the driver's door jam

Explanation:

The instruction on proper inflation of car tires can be found on the tire information placard in the door jam area or the fuel filler door, in the glove box or in the car or tire manual

The tire information of the proper pressure to fill the tires is also visibly engraved on the sides of the car tire, where other information such as the requirement for training on tire filling/changing, safety precautions and manufacturer's information

3 0

4 years ago

Read 2 more answers

The distance between Earth and Mars is 225 million km. When converted using the conversion factor 1 AU = 1.5 × 108 km, the dista

noname [10]

To convert km to AU, we divide 225,000,000 km by the factor of 1.5 x 10^8 = 150,000,000 km. This gives us 225,000,000 / 150,000,000 = 1.5 AU. Therefore, the distance between Earth and Mars in AU is 1.5 AU.
The AU is not equivalent to a light-year. A light-year is equivalent to around 9.5 x 10^12 kilometers.

4 0

4 years ago

How old is the universe

Virty [35]

Roughly 13.8 billion years old according to science

5 0

3 years ago

Read 2 more answers

Light of wavelength 630 nm is incident on a long, narrow slit. Determine the angular deflection of the first diffraction minimum

asambeis [7]

Answer:

a) 1.8°

b) 0.18°

c) 0.018°

Explanation:

Wavelength (λ) = 630nm = 630 *10^-9m

The equation that describes the angular deflection of a dark band is

Wsin(βm) = mλ

w = width of the single slit

λ = wavelength of the light

βm = angular deflection of the mth dark band.

a) In order to get the angular deflection of the first dark band for a slit with 0.02mm width, substitute w = 0.02mm = 0.02*10^-3 , m = 1 , λ= 630*10^-9

0.02*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.02*10^-3

Sin(β1) = 0.0315

β1 = Sin^-1(0.0315)

= 1.8°

b) substitute w = 0.2mm = 0.2*10^-3 , m = 1 , λ= 630*10^-9

0.2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.2*10^-3

Sin(β1) = 0.00315

β1 = Sin^-1(0.00315)

= 0.18°

c) substitute w = 2mm = 2*10^-3 , m = 1 , λ= 630*10^-9

2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 2*10^-3

Sin(β1) = 3.15*10^-4

β1 = Sin^-1(3.15*10^-4)

= 0.018°

6 0

3 years ago

a transformer changes 95 v acorss the primary to 875 V acorss the secondary. If the primmary coil has 450 turns how many turns d

natita [175]

Answer:

The number of turns in the secondary coil is 4145 turns

Explanation:

Given;

the induced emf on the primary coil, $E_p$ = 95 V

the induced emf on the secondary coil, $E_s$ = 875 V

the number of turns in the primary coil, $N_p$ = 450 turns

the number of turns in the secondary coil, $N_s$ = ?

The number of turns in the secondary coil is calculated as;

$\frac{N_p}{N_s} = \frac{E_p}{E_s}$

$N_s = \frac{N_pE_s}{E_p} \\\\N_s = \frac{450*875}{95} \\\\N_s = 4145 \ turns$

Therefore, the number of turns in the secondary coil is 4145 turns.

8 0

3 years ago

3- For given three vectors a, b and c, c = a x b, then the vector c is:​

3- For given three vectors a, b and c, c = a x b, then the vector c is: