What happens is the potential value of the conductor decreases due to the presence of second conductor
as the capacitance is given by C = q/v
the value of v deceases as v-v1
thus the new capacitance is = C' = q/v-v1 thus the lowering of v increases the capacitance
I believe the answer is californium because it is used in most metals and is very strong and expensive like gold and silver
40
Because if you divide 3,600 by 90 it is equivalent to 40.
Hope this helps, have a blessed day :)
Answer:
if it's velocity u talking of.....
Explanation:
then it's displacement/ time
