Answer:
T=1.384×10⁶seconds
Explanation:
Given data
p (Intensity)=1.30 kw/m²
E (Energy)=1.8×10⁹ J
A (Area)=1.00 m²
T (Time required)=?
Solution
E=PT ................eq(i)
where E is energy
P is radiation power
T is time
Radiating Power is given as
P=pA
Where p is intensity
A is Area
Put P=pA in eq(i) we get
E=pAT
T=E/pA
The change in kinetic energy is
Explanation:
According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Mathematically:
where :
W is the work done on the object
is the final kinetic energy of the object
is the initial kinetic energy
Also, the work done on an object is (assuming that the force is applied parallel to the motion of the object):
where
F is the magnitude of the force
is the displacement of the object
In this problem, the force acting on the object is
F
While the displacement is the horizontal distance travelled, so
Therefore, the work done is
And so the change in kinetic energy is
Learn more about work and kinetic energy:
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