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3 years ago

B. How could you determine the instantaneous speed during the trip? Be specific.

Physics

1 answer:

alex41 [277]3 years ago

6 0

Answer:

Speedometer.

Explanation:

If you look at the speedometer in a car, you will see your instantaneous speed. Speedometers tell you your speed of that moment and thats what instantaneous speed.

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A scientist must have _____ concentration when dealing with with delicate equipment.

Rom4ik [11]

Probably C, coherent

4 0

3 years ago

How many nanoseconds does it take light to travel 3.50 ft in vacuum??

Tresset [83]

light speed in vacuum = 3.8 * 10^8

Distance (Given) = 3.5 ft

now, time = distance/speed = 3.50 / 3.8 * 10^8 = 9.21 * 10^-9 s = 9.21 nanoseconds

So, your answer is 9.21 nano-seconds...

8 0

4 years ago

2. Sally put her mug of coffee on the table. The mug has a mass of 1 kg. if the pressure

egoroff_w [7]

We have,

The mass of sally's mug is 1 kg
The pressure appliedby the mug is 1100 pascal.

We know that,

Pressure = Force/Area

As, we already have the value of pressure, let's calculate that of force now;

F = ma
F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
F = 10 N

Just put all the values in the formula now;

P = F/A
1100 = 10 / A
1100/10 = A
110 m² = A

As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

Surface area = Circumference

So, let's solve it;

Circumference = 2πr
110 = 2 × 22/7 × r
110 × 7/2 × 22 = r
5 × 7 = r
35 cm = r

Thus, the radius of the circle is 35 cm.

7 0

3 years ago

The _____ of an object consists of its speed and direction.

ELEN [110]

Velocity would be an answer

3 0

3 years ago

The three stages of a train route took 1 hour ,2 hours ,and 4 hours . The first two stages were 80km and 200km of the train aver

luda_lava [24]

Answer:

the third stage was 480 km long

Explanation:

Stage 1:

Time = 1 hours

Speed = 80km

Stage 2:

Time = 2 hours

Speed = 200km

Stage 3:

Time = 4 hours

Let the Distance at the stage 3 be x

Average speed of the train route = 100 km/h

$\frac{ \text{speed at stage 1} + \text{speed at stage 2} + \text{speed at stage 3}}{3} = 0$

$\frac{ \text{speed at stage 1} + \text{speed at stage 2} + \text{speed at stage 3}}{3} = 100$

Lets find the speed at stage 1

Speed = $\frac{Distance }{Time}$

Speed = $\frac{80}{1}$

Speed 1= 80 km/hr

The speed at stage 2

Speed = $\frac{Distance }{Time}$

Speed = $\frac{200}{2}$

Speed 2 = 100 km/hr

The speed at stage 3

Speed = $\frac{Distance }{Time}$

Speed = $\frac{x}{4}$

Speed 3 = $\frac{x}{4}$

we kow that average is ,

$\frac{ \text{speed 1} + \text{speed 2} + \text{speed 3}}{3} = 100$

$\frac{ 80 + 100+ \frac{x}{4} }{3} = 100$

$\frac{ 180 + \frac{x}{4} }{3} = 100$

$\frac{ \frac{720 +x}{4} }{3} = 100$

$\frac{720 +x}{4} \times \frac{1}{3} = 100$

$\frac{720 +x}{12} = 100$

$720 +x = 100 \times 12$

$720 +x = 1200$

$x = 1200- 720$

x = 480

6 0

3 years ago