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Sloan [31]
3 years ago
9

B. How could you determine the instantaneous speed during the trip? Be specific.

Physics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

Speedometer.

Explanation:

If you look at the speedometer in a car, you will see your instantaneous speed. Speedometers tell you your speed of that moment and thats what instantaneous speed.

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HELP!!!!
BigorU [14]
Time = 13.5 / 2.5 = 5.4 seconds
4 0
3 years ago
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A spring has a relaxed length of 35 cm (0.35 m) and its spring stiffness is 12 N/m. You glue a 66 gram block (0.066 kg) to the t
Sonbull [250]

We have that the value for y is

y=0.12376m

 

From the Question we are told that

Relaxed length of 35 cm (0.35 m)

Spring stiffness is 12 N/m.

Glue a 66 gram block (0.066 kg)

Total length is l_t=16 cm

Block during a 0.24-second interval

Generally the equation for the Force of spring of block  is mathematically given as

F_{spring}=kx\\\\\ F_{spring}=12*(0.35-0.16)\\\\ F_{spring}=2.28N

Generally

F_{elastic}=-mg\\\\F_{elastic}=-0.066*9.8\\\\F_{elastic}=-0.6468N

Generally,Net Force

F_{net}=F_{spring}-F_{elastic}\\\\F_{net}=2.28N-(-0.6468N)\\\\F_{net}=2.9268N

Generally,Velocity of block

V_y=\frac{py}{m}

Where

Py= F_{net}*dt\\\\Py= 2.9268*0.08\\\\Py=0.234144

Therefore

V_y=\frac{0.234144}{0.066}\\\\V_y=3.547m/s

Generally the equation for the Velocity of block   is mathematically given as

Vy=\frac{yf-yt}{t-t_0}\\\\y=(3.547(0.08-0))-0.16

y=0.12376m

For more information on this visit

brainly.com/question/22271063?referrer=searchResults

4 0
3 years ago
A car accelerates uniformly from 5m/s to 15m/s taking 7.5 seconds. How far did it travel during this period
vodomira [7]
The required answer is 66.925 m which is the distance travelled by the car.
4 0
2 years ago
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How long does a car (1000 kg) have a speed of 30 m/s from a rest if the engine power is 10kw
Lemur [1.5K]

Answer: 90.1 s

Explanation:

Use equation for power:

P=F*V

Use eqation for force:

F=ma

F---force

V---velocity

Vr=om/s

V=30m/s

m=1000kg

P=10000W

---------------------------

P=FV

F=P/V

F=10000W/30m/s

F=333.33N

Use equation for force to find accelartaion.

F=ma

a=F/m

a=333.33N/1000kg

a=0.333 m/s²

Use equation for accelaration to find out time:

a=(V-Vs)/t

t=(V-Vs)/a

t=(30m/s)/(0.333m/s²)

t=90.09 s≈90.1 s

------------------------

5 0
3 years ago
Which object has the greatest inertia? *
____ [38]
One with greater mass (8kg)
4 0
4 years ago
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