Time = 13.5 / 2.5 = 5.4 seconds
We have that the value for y is
From the Question we are told that
Relaxed length of 35 cm (0.35 m)
Spring stiffness is 12 N/m.
Glue a 66 gram block (0.066 kg)
Total length is l_t=16 cm
Block during a 0.24-second interval
Generally the equation for the Force of spring of block is mathematically given as

Generally

Generally,Net Force

Generally,Velocity of block

Where

Therefore

Generally the equation for the Velocity of block is mathematically given as


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The required answer is 66.925 m which is the distance travelled by the car.
Answer: 90.1 s
Explanation:
Use equation for power:
P=F*V
Use eqation for force:
F=ma
F---force
V---velocity
Vr=om/s
V=30m/s
m=1000kg
P=10000W
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P=FV
F=P/V
F=10000W/30m/s
F=333.33N
Use equation for force to find accelartaion.
F=ma
a=F/m
a=333.33N/1000kg
a=0.333 m/s²
Use equation for accelaration to find out time:
a=(V-Vs)/t
t=(V-Vs)/a
t=(30m/s)/(0.333m/s²)
t=90.09 s≈90.1 s
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One with greater mass (8kg)