A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.
<h3>What is the Rutherford experiment?</h3>
Rutherford performed an experiment in which alpha particles are bombarded on the gold foil.
Some of the particles bounced back which indicates that there are heavy particles present in the center of an atom.
Most alpha particles pass through the atom which indicates that there is a lot of empty space in an atom.
A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.
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1) 3 miles/Hour
The speed is defined as the distance covered divided by the time taken:
where
d = 1.5 mi is the distance
t = 0.5 h is the time taken
Substituting,
2) 1.34 m/s south
Velocity, instead, is a vector, so it has both a magnitude and a direction. We have:
is the displacement in meters
is the time taken in seconds
Substituting,
And the direction of the velocity is the same as the displacement, so it is south.
Answer:
Which sentence from the passage shows that the function of the river depicted here has carried through to modern times?
Explanation:
Which sentence from the passage shows that the function of the river depicted here has carried through to modern times?
Answer:
Explanation:
When a lightning bolt travels from the cloud to the ground it actually opens up a little hole in the air, called a channel. Once then light is gone the air collapses back in and creates a sound wave that we hear as thunder. The reason we see lightning before we hear thunder is because light travels faster than sound!
The value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.
<h3>Acceleration of the vehicle</h3>
The acceleration of the vehicle before coming to rest is calculated as follows;
v² = u² + 2as
where;
- v is the final velocity
- u is the initial velocity
- a is the acceleration
- s is the distance traveled before stopping
the car came to rest with constant velocity attained after 12 seconds.
the initial velocity of the car before 12 seconds is zero.
v² = 0 + 2as
a = v²/2s
a = (10²)/(2 x 66)
a = 0.76 m/s²
<h3>Time of motion of the vehicle</h3>
d = ut + ¹/₂at²
where;
- d is the total distance traveled
- t is the time of motion
- a is acceleration
- u is initial velocity of the vehicle
580 = 0 + ¹/₂(0.76)t²
580 = 0.38t²
t² = 580/0.38
t² = 1,526.3
t = √1,526.3
t = 39 seconds
Thus, the value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.
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