Ask question

Ask question

All categories

2 years ago

10

Sempre que os corpos vibram e as vibrações se propagam num meio material como o ar, produzem ondas sonoras que são ondas de pres

são?

1 answer:

stealth61 [152]2 years ago

8 0

Answer:

Sempre que os corpos vibram e as vibrações se propagam num meio material como o ar, produzem ondas sonoras que são ondas de pressão?

Explanation:

You might be interested in

A 26.3 kg object is traveling at 21.0 m/s north. What average net force is required to bring this object to a stop in 2.60 secon

taurus [48]

The average force is -212.4 N

Explanation:

We can solve this problem by using the impulse theorem, which states that the impulse exerted on the object (the product of the force exerted and the time) is equal to the change in momentum of the object:

$F \Delta t = m \Delta v$

where

F is the net force on the object

$\Delta t$ is the time

m is the mass

$\Delta v$ is the change in velocity

In this problem, we have:

m = 26.3 kg

$\Delta v = -21.0 m/s$

$\Delta t = 2.60 s$

Solving for F, we find

$F=\frac{m\Delta v}{\Delta t}=\frac{(26.3)(-21.0)}{2.60}=-212.4 N$

where the negative sign indicates that the direction of the force is opposite to the motion of the object.

Learn more about force and momentum:

brainly.com/question/9484203

#LearnwithBrainly

4 0

2 years ago

Molecules are composed of atoms held together through

Crank

They are held through electrons

8 0

3 years ago

Read 2 more answers

According to Bohr each orbit an electron could travel in had a certain amount of ________ associated with it.

Lena [83]

The awnser to your problem would be a as in energy

6 0

3 years ago

Chloroplasts convert energy from the sun into ________________.Immersive Reader

Aleksandr [31]

Answer:

1) glucose

2) ATP

Explanation:

moo

6 0

3 years ago

6. The hole on a level, elevated golf green is a horizontal distance of 150 m from the tee and at an elevation of 12.4 m above t

Georgia [21]

Answer:

u = 104.68 m/s

Explanation:

given,

horizontal distance = 150 m

elevation of 12.4 m

angle = 8.6°

horizontal motion = x = u cos θ. t .............(1)

vertical motion =

$y = u sin \theta - \dfrac{1}{2}gt^2$ ................(2)

from equation(1) and (2)

$y = x tan \theta - \dfrac{gx^2}{2u^2cos^2\theta}$ ..........{3}

$12.4 = 150\times tan (8.6) - \dfrac{9.8\times 150^2}{2u^2cos^2(8.6)}$

$\dfrac{9.8\times 150^2}{2u^2cos^2(8.6)} = 10.29$

$\dfrac{9.8\times 150^2}{2\times 10.29\times cos^2(8.6)} = u^2$

$u = \sqrt{10959.34}$

u = 104.68 m/s

The initial speed of the ball is u = 104.68 m/s

8 0

2 years ago