Answer:
Angular velocity is same as frequency of oscillation in this case.
ω = 
x ![[\frac{L^{2}}{mK}]^{3/14}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BL%5E%7B2%7D%7D%7BmK%7D%5D%5E%7B3%2F14%7D)
Explanation:
- write the equation F(r) = -K
with angular momentum <em>L</em>
- Get the necessary centripetal acceleration with radius r₀ and make r₀ the subject.
- Write the energy of the orbit in relative to r = 0, and solve for "E".
- Find the second derivative of effective potential to calculate the frequency of small radial oscillations. This is the effective spring constant.
- Solve for effective potential
- ω = x
Answer:
Explanation:
We use the kinematics equation to solve this question:
because the ball is dropped
the acceleration is the gravity, negative because it points downwards
initial height
final height
So:
when it reaches the maximum height, all the energy has now been converted into potential energy.when a ball is thrown straight upto into the air,all its initial kinetic energy converted into gravitational potential energy when it reaches its maximum height
Answer:
Explanation:
The frequency of a wave can be found using the following formula.
where <em>f</em> is the frequency, <em>v</em> is the velocity/wave speed, and λ is the wavelength.
The wavelength is 10 meters and the velocity is 200 meters per second.
- 1 m/s can also be written as 1 m*s^-1
Therefore:
Substitute the values into the formula.
Divide and note that the meters (m) will cancel each other out.
- 1 s^-1 is equal to Hertz
- Therefore, our answer of 20 s^-1 is equal to 20 Hz
The frequency of the wave is <u>20 Hertz</u>
The Force of Static Friction<span> keeps a stationary object at rest! Once the Force of</span>Static Friction<span> is overcome, the Force of </span>Kinetic Friction<span> is what slows down a moving object.</span>
