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Vesna [10]
3 years ago
6

In January, a small number of eastern cottontail rabbits were introduced into Red Forest. The population curve of the rabbits is

shown below.
According the information shown in the graph, what is the carrying capacity for eastern cottontail rabbits in Red Forest?

A. 75
B. 100
C. 125
D. 15

Biology
2 answers:
SOVA2 [1]3 years ago
6 0

Answer:

B: 100

Explanation:

Carrying capacity is the point where a population stops growing and stays stable.

FromTheMoon [43]3 years ago
5 0

Answer:

B:100

Explanation:

Carrying capacity refers to the maximum number of members of a population that a particular environment can sustain for survival. In any ecosystem, the basic resources that organisms need for survival are always in limited supply. Examples include food, water, sunlight, oxygen, and shelter.

As a growing population reaches the limits of the available resources in an environment, its size levels off to "match" the amount of resources available. In doing so, the population reaches its carrying capacity.

In this example, the population of eastern cottontail rabbits levels off at around 100 individuals.

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A geneticist crossed fruit flies to determine the phenotypic ratio. The geneticist crossed a fly with blistery wings and spinele
kondor19780726 [428]

Complete question:

A geneticist crossed fruit flies to determine the phenotypic ratio. The geneticist crossed a fly with blistery wings and spineless bristles (bbss) with a heterozygous fly that had normal wings and normal bristles (BbSs). Which proportion of offspring that are dominant for both traits in would you not expect based on Mendel's law of independent assortment? 1/2 , 4/16, 25% , or 1/4

Answer:

1/2 is the proportion of the offspring that is NOT expected among individuals that are dominant for both traits.

4/16 = 1/4 = 25% of the progeny and the correct expected proportion of individuals that are dominant for both traits.

Explanation:

<u>Available data</u>:

  • Cross:  a fly with blistery wings and spineless bristles with a heterozygous fly that had normal wings and normal bristles
  • Recessive trait: blistery wings and spineless bristles
  • Dominant trait: normal wings and normal bristles

Let us say that:

  • B is the dominant allele for normal wings
  • b is the recessive allele for blistery wings
  • S is the dominant allele for normal bristles
  • s is the recessive allele for spineless bristles

Parentals)        bbss       x        BbSs

Gametes)  bs, bs, bs, bs     BS, Bs, bS, bs

Punnett square)    BS        Bs         bS        bs

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

                     bs    BbSs    Bbss     bbSs    bbss

F1)  4/16 = 1/4 = 25%  of the progeny is expected to be BbSs, dyhibrid individuals, expressing normal wings and normal bristles

     4/16 = 1/4 = 25% of the progeny is expected to be Bbss, expressing normal wings and spineless bristles

     4/16 = 1/4 = 25% of the progeny is expected to be bbSs, expressing  blistery wings and normal bristles

     4/16 = 1/4 = 25% of the progeny is expected to be bbss, expressing  blistery wings and spineless bristles    

5 0
3 years ago
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