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3 years ago

A brick has a mass of 562 g and a volume of 43 cm3. What is the density?

Physics

1 answer:

alexgriva [62]3 years ago

3 0

Answer:

13.069 g/cm^3

Explanation:

to get density, simply divide the mass by the volume. Your equation would look like this; p=562/43

'P' represents density in this equation. Never forget to add your units!

Hope this helps!

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Tasya [4]

Answer:

Explanation:

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3 years ago

Can someone please give me the (Answers) to this? ... please ...

denpristay [2]

Answer:

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3. none they both have same momentum

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3 years ago

A particle is moving in a circular path of radius r . The displacement after half a circle would be

Art [367]

Answer:

Explanation:

As we know that

The displacement is the total distance measured between the initial or start and final or destination point

If particle cover half path of the circle, the displacement can easily find out by considering the distance between the start and destination point

We attached the diagram for better understanding

As per the diagram.

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4 years ago

A solenoid of length 5.0 cm has a cross sectional area of 1.0 cm2 and has 300 uniformly spaced turns. The solenoid is wrapped in

OleMash [197]

The calculated mutual inductance is 8.544 x 10⁻⁵ H.

Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.

Length of the solenoid= 5.0 cm

Area of cross-section=1.0 cm²

no of spaced turns=300 turns

turns of insulated wire=180 turns

Mutual inductance (M) = μ₀μr N1N2 A/ L

=(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5

=79.12 x 10⁻¹⁰ x 54000 / 5

=8.544 x 10⁻⁵ H

hence, the mutual inductance is 8.544 x 10⁻⁵ H.

Learn more about Mutual inductance here-

brainly.com/question/14014588

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1 year ago

A large box of mass M is pulled across a horizontal, frictionless surface by a horizontal rope with tension T. A small box of ma

Alexxx [7]

Answer:

Explanation:

Given

Mass of big box is M and small box is m

Tension T will cause the boxes to accelerate

$T=(M+m)a$

where a=acceleration of the boxes

Now smaller box will slip over large box if the acceleration force will exceed the static friction

i.e. for limiting value

$\mu _smg=ma$

$a=\mu _s\cdot g$

thus maximum tension

$T=\mu _s(M+m)g$

6 0

4 years ago