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Natalka [10]
3 years ago
13

When grocery shopping, the mass of the cart changes as you start to fill up your cart. How does the change in mass of your cart

change the force you apply to the cart?
Group of answer choices
a. The force will need to increase

b. The force will need to decrease

c. The force does not need to change
Physics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

b

Explanation:

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What kind of line on a distance vs. time graph indicates that the object is accelerating?
suter [353]

Answer: a curved line

Explanation: a straight line indicates that the object is moving at a constant velocity because it has one slope, but a curved line on a distance-time graph indicates that the velocity is constantly changing because the slope is changing, which is acceleration. the line could be curved in any direction, as long as it shows a change in slope.

7 0
3 years ago
NEED HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
stepan [7]

Answer:

Electric charge

Like; opposite

Faster

True

True

positive to negative

Explanation:

6 0
3 years ago
A uniform line charge of density λ lies on the x axis between x = 0 and x = L. Its total charge is 7 nC. The electric field at x
DedPeter [7]

Answer:

The electric field at x = 3L is 166.67 N/C

Solution:

As per the question:

The uniform line charge density on the x-axis for x, 0< x< L is \lambda

Total charge, Q = 7 nC = 7\times 10^{- 9} C

At x = 2L,

Electric field, \vec{E_{2L}} = 500N/C

Coulomb constant, K = 8.99\times 10^{9} N.m^{2}/C^{2}

Now, we know that:

\vec{E} = K\frac{Q}{x^{2}}

Also the line charge density:

\lambda = \frac{Q}{L}

Thus

Q = \lambda L

Now, for small element:

d\vec{E} = K\frac{dq}{x^{2}}

d\vec{E} = K\frac{\lambda }{x^{2}}dx

Integrating both the sides from x = L to x = 2L

\int_{0}^{E}d\vec{E_{2L}} = K\lambda \int_{L}^{2L}\frac{1}{x^{2}}dx

\vec{E_{2L}} = K\lambda[\frac{- 1}{x}]_{L}^{2L}] = K\frac{Q}{L}[frac{1}{2L}]

\vec{E_{2L}} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{2L}] = \frac{63}{L^{2}}

Similarly,

For the field in between the range 2L< x < 3L:

\int_{0}^{E}d\vec{E} = K\lambda \int_{2L}^{3L}\frac{1}{x^{2}}dx

\vec{E} = K\lambda[\frac{- 1}{x}]_{2L}^{3L}] = K\frac{Q}{L}[frac{1}{6L}]

\vec{E} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{6L}] = \frac{63}{6L^{2}}

Now,

If at x = 2L,

\vec{E_{2L}} = 500 N/C

Then at x = 3L:

\frac{\vec{E_{2L}}}{3} = \frac{500}{3} = 166.67 N/C

4 0
4 years ago
Which rock is made mostly of dark, fine-grained silicate minerals, chiefly plagioclase feldspar and pyroxene, and magnetite?
Dafna1 [17]

A dark-colored (igneous rock,) commonly extrusive from volcanic eruptions and composed primarily of the minerals of calcic plagioclase and pyroxene, and sometimes olivine. Basalt is the fine-grained equivalent of gabbro.

8 0
4 years ago
A sound wave has a frequency of 776 Hz in air and a wavelength of 0.52 m. What is the temperature of the air? Relate the speed o
OLEGan [10]

Answer:

142.7650889

Explanation:

I think the answer above is correct. So to find the velocity of the wave you can do: frequency*wavelength = velocity

in your case, the velocity is equal to 403.5m/s

so we know that the 403.52 is the total velocity of the wave

and the equation: velocity at 0 degrees Celsius * \sqrt{{T}/{273}} where T represents temperature in Kelvins = veloctity

so we set 403.52 = 327*\sqrt{{T}/{273}} and solve for T

T will then equal the degree in Kelvins

so to convert from Kelvins to degrees celsius you subtract 273 from the Kelvins value and you are left with the degrees in Celsius which equals 142.7650889 degrees Celsius

5 0
3 years ago
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