Answer:
A heat engine is a device that converts internal energy into work. Internal energy is increased by the addition of heat. The efficiency of a heat engine is a measurement of how efficiently it works. Efficiency compares the amount of useful energy extracted from a process to the total energy input. The heat engine will be more efficient if the percentage is higher.
Explanation:
 
        
             
        
        
        
Answer:
Zero work done,since the body isn't acting against  or by gravity.
Explanation:
Gravitational force is usually  considered as work done against gravity (-ve) and work by gravity ( +ve ) and also When work isn't done by or against gravity work done in this case is zero.
Gravitational force can be define as that force that attracts a body to any other phyical body or system that have mass.
The planet been considered as our system in this case is assumed to have mass, and ought to demonstrate such properties associated with gravitational force in such system. Such properties include the return of every object been thrown up as a result of gravity acting downwards. The orbiting nature of object along an elliptical part when gravitational force isn't acting on the body and it is assumed to be zero.
 
        
             
        
        
        
Answer: 14.7kJ, 29.4kJ, 44.1kJ
Explanation:
<em>The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field.  </em>
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In the case of the Earth, in which the gravitational field is considered constant, the value of the gravitational potential energy  will be:
 will be:  
 
  
Where  is the mass of the object,
 is the mass of the object,  the acceleration due gravity and
 the acceleration due gravity and  the height of the object.
 the height of the object.  
Knowing this, let's begin with the calculaations:
For m=3kg
 
  
 
  
For m=6kg
 
  
 
  
For m=9kg
 
  
 
  
 
        
             
        
        
        
Answer
given,
diameter,d₁ = 7.5 cm
                d₂ = 4.5 cm
 P₁ = 32 kPa
P₂ = 25 kPa
Assuming, we have calculation of flow in the pipe
using continuity equation
  A₁ v₁ = A₂ v₂
  π r₁² v₁ = π r₂² v₂
   
   
   
Applying Bernoulli's equation
   
   
   
   
   
        v₂ = 4.01 m/s
 fluid flow rate
 Q = A₂ V₂
Q = π (0.0225)²  x 4.01
Q = 6.38 x 10⁻³ m³/s
flow in the pipe is equal to 6.38 x 10⁻³ m³/s