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kolbaska11 [484]
3 years ago
7

HELP ‼️‼️ill give you brainliest

Mathematics
1 answer:
mezya [45]3 years ago
8 0
What is the topic about
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a flashlight has 6 batteries, 2 are defective. what is the probability you select at least 1 good battery
irga5000 [103]

Answer:hhthfgh


Step-by-step explanation:

htrhghyrjyjytrhytrh

3 0
3 years ago
What is the magnitude of an earthquake that is 10,000 times more intense than a standard earthquake?
Mekhanik [1.2K]

Answer:4

Step-by-step explanation:

5 0
3 years ago
How do you simplify this equation?
Troyanec [42]
4^3*4^-5= 4^-2 (add the exponents since the base is the same)
5^-4*5^1= 5^-3 (add the exponents since the base is the same)

Square both terms (double the exponents)
(4^-2)^2= 4^-4
(5^-3)2= 5^-6

Then take out negative exponents (x^-a= 1/x^a)
4^-4 /5^-6 = 5^6/4^4

Final answer: 5^6/4^4

If you want it in number form
5^6= 15625
4^4=256
15625/256= 61.035...
5 0
3 years ago
Which statement is true about the factorization of 30x2 + 40xy + 51y2? The polynomial can be rewritten after factoring as 10(3x2
iragen [17]

Answer:

  The greatest common factor of the terms is 1.

Step-by-step explanation:

The terms have no variables in common, and the coefficients have no factors in common. The greatest common factor of the terms is 1.

__

The discriminant is negative (40² -4(30)(51) = -4520), so any linear factors will be complex.

6 0
3 years ago
Read 2 more answers
How do you know where to put the constant when finding general solutions for differential equations?
Norma-Jean [14]
Let's suppose we want to solve y'=y with y(0)=2. Separating variables and integrating, we get

\displaystyle\int\dfrac{\mathrm dy}y=\int\mathrm dx\implies\ln|y|=x+C\implies y=e^{x+C}

Leaving the solution in this form, the initial condition gives

2=e^{0+C}=e^C\implies C=\ln2

This means the solution is y=e^{x+\ln2}.

Now if we were to write y=e^{x+C}=e^xe^C=Ce^x, then we would have found

2=Ce^0\implies C=2

so that the solution would have been y=2e^x.

But these two solutions are the same, since y=e^{x+\ln2}=e^xe^{\ln2}=2e^x. So we get the same solution regardless of where we place C, despite getting different values for C.
5 0
3 years ago
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