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Shkiper50 [21]
3 years ago
14

Is 13.48 irrational or rational? ​

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0

Answer:

It is irrational

Step-by-step explanation:

Rational numbers do not have decimals.

Sedaia [141]3 years ago
5 0
It’s rational and rational numbers can have decimals.
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Can you help with this please
mojhsa [17]

Answer:

x = 81

Steps:

It says that y ~ √x

We have points (9, 18) as a guide.

We can write y = f(x) = a√x +b

Use points (9, 18) as a guide

18 = a√9 +b

18 = 3a + b

One solution might be a = 6, which means f(x) = 6√x

Thus when y = 54,

54 = 6√x

9 = √x

81 = x

6 0
2 years ago
2t+8&gt;-4(t+1)<br> T&gt;___<br> **The sign is meant to be more than or equal to.**
Mrrafil [7]
<span>2t+8>-4(t+1)
2t + 8 > -4t - 4
2t + 4t > -4 - 8
6t > -12
  t > -2

answer
</span>  t > -2
8 0
4 years ago
Which of the following is the equation of a line perpendicular to the line y =
makvit [3.9K]

Answer:

y = \frac{1}{10} x + \frac{13}{2}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 10x + 1 ← is in slope- intercept form

with slope m = - 10

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-10} = \frac{1}{10}, thus

y = \frac{1}{10} x + c ← is the partial equation

To find c substitute (5, 7) into the partial equation

7 = \frac{1}{2} + c ⇒ c = 7 - \frac{1}{2} = \frac{13}{2}

y = \frac{1}{10} x + \frac{13}{2} ← equation of line

5 0
3 years ago
What does m equal to: -1/3m+1=-7
otez555 [7]
-1/3m+1=-7
-1/3m+1-1=-7-1     subtract 1 from both sides
-3(-1/3m)=-3(-8)    multiply -3 on both sides
m=24                     solution
5 0
3 years ago
Read 2 more answers
How to do y=mx+b for the problem 4x-11y=-6
Aleks [24]
Simply rearrange the terms and simplify.

Subtracting 4x from both sides, we have:

-11y=-4x-6

Dividing by -11, we have:

y= \frac{4}{11} \cdot x + \frac{6}{11}

This is in the proper form, so this is our final equation.
6 0
3 years ago
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