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enot [183]
3 years ago
11

The weight of a 2-kilogram object on earth is _________.

Physics
1 answer:
ikadub [295]3 years ago
5 0
19.6 N........weight is equal to mass multiplied by gravitational force which is 9.8 m/s2......2 x 9.8 gives 19.6 N
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A national college researcher reported that 67%of students who graduated from high school in 2012 enrolled in college. Twenty-ni
dsp73

Answer:

Explanation:

Theorem of Binomial Distribution will apply here.

n = 29 , p = .67 , q = 0.33

mean = np = 29 x .67 = 19.43

Standard Deviation = √npq

= √29 x .67 x .33

= √6.4

= 2.53

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4 0
3 years ago
What distance does light travel in water, glass, and diamond during the time that it travels 1.0 m in vacuum? the refractive ind
alexdok [17]
We are given with
distance traveled through vacuum = 1.0 m
refractive index of water = 1.33
refractive index of glass = 1.50
refractive index of diamond = 2.42

distance traveled through water is = 1.0/1.33 = 0.75 m
distance traveled through water is = 1.0/1.50 = 0.67 m
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8 0
3 years ago
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How does mining affect the environment
weqwewe [10]
The environmental impact of mining affects, nesting habitats for wildlife. Wildlife either moves on, or dies.
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5 0
3 years ago
The concentration of Biochemical Oxygen Demand (BOD) in a river just downstream of a wastewater treatment plant’s effluent pipe
shtirl [24]

Answer:

The BOD concentration 50 km downstream when the velocity of the river is 15 km/day is 63.5 mg/L

Explanation:

Let the initial concentration of the BOD = C₀

Concentration of BOD at any time or point = C

dC/dt = - KC

∫ dC/C = -k ∫ dt

Integrating the left hand side from C₀ to C and the right hand side from 0 to t

In (C/C₀) = -kt + b (b = constant of integration)

At t = 0, C = C₀

In 1 = 0 + b

b = 0

In (C/C₀) = - kt

(C/C₀) = e⁻ᵏᵗ

C = C₀ e⁻ᵏᵗ

C₀ = 75 mg/L

k = 0.05 /day

C = 75 e⁻⁰•⁰⁵ᵗ

So, we need the BOD concentration 50 km downstream when the velocity of the river is 15 km/day

We calculate how many days it takes the river to reach 50 km downstream

Velocity = (displacement/time)

15 = 50/t

t = 50/15 = 3.3333 days

So, we need the C that corresponds to t = 3.3333 days

C = 75 e⁻⁰•⁰⁵ᵗ

0.05 t = 0.05 × 3.333 = 0.167

C = 75 e⁻⁰•¹⁶⁷

C = 63.5 mg/L

5 0
3 years ago
3 points
blagie [28]

Answer:

A and D

Explanation:

Acceleration is the active change in speed, increasing or decreasing.

8 0
3 years ago
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