Answer:
d
Explanation:
Generally, it is transported through pipes so I think statement d is incorrect.
Where is the chooses for you question
The question is incomplete, complete question is :
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
Structure is given in an image?
Answer:
There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Explanation:
Total numbers of carbon = 10
Number of primary carbons that is carbon joined to just single carbon atom = 6
Number of secondary carbons that is carbon joined to two carbon atoms = 1
Number of tertiary carbons that is carbon joined to three carbon atoms = 2
Number of quartenary carbons that is carbon joined to four carbon atoms = 1
So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Answer:
The value of the Michaelis–Menten constant is 0.0111 mM.
Explanation:
Michaelis–Menten 's equation:
![v_o=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}](https://tex.z-dn.net/?f=v_o%3DV_%7Bmax%7D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7B%28K_m%2B%5BS%5D%29%7D%3Dk_%7Bcat%7D%5BE_o%5D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7B%28K_m%2B%5BS%5D%29%7D)
![V_{max}=k_{cat}[E_o]](https://tex.z-dn.net/?f=V_%7Bmax%7D%3Dk_%7Bcat%7D%5BE_o%5D)
Where:
= rate of formation of products
[S] = Concatenation of substrate
= Michaelis constant
= Maximum rate achieved
= Catalytic rate of the system
= Initial concentration of enzyme
On substituting all the given values
We have :

[S] = 0.10 mM
![\frac{v_o}{V_{max}}=\frac{[S]}{(K_m+[S])}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_o%7D%7BV_%7Bmax%7D%7D%3D%5Cfrac%7B%5BS%5D%7D%7B%28K_m%2B%5BS%5D%29%7D)


The value of the Michaelis–Menten constant is 0.0111 mM.
Answer:

Explanation:
Force is equal to mass times acceleration.

By dividing both sides by m, we rearrange the formula for a (acceleration).

The force is 6.2 Newtons, but we can convert the units to make the problem easier later on.
- A Newton is equal to 1 kg*m/s², so 6.2 N is equal to 6.2 kg*m/s².
The mass is 2300 grams, but we need to convert it to kilograms.
- To convert grams to kilograms, divide by 1,000
- 2300 g/1000= 2.3 kg

Substitute the values into the formula.

Divide. Note that the kilograms or "kg" will cancel each other out (this is why we converted the units).


Round to the nearest tenth. The 9 in the hundredth place tells us to round up to 2.7

The acceleration is about <u>2.7 meters per second squared.</u>