The percent yield : 4. 84.58%
<h3>Further explanation</h3>
Reaction
CaCO₃ ⇄ CaO+CO₂
mass CaCO₃ = 2.3 × 10³ g
mol CaCO₃ (MW=100.0869 g/mol) :
From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98
mass CaO(MW=56.0774 g/mol)⇒ (theoretical) :
The percent yield :
Answer:
I can help
Explanation:
++++++++++++++++++++++++++++
Which part of the body system are you talking about
Answer:
1. 0.0154mole of PbS
2. Double displacement reaction
Explanation:
First, let write a balanced equation for the reaction. This is illustrated below:
Pb(CH3COO)2 + H2S —> PbS + 2 CH3COOH
Molar Mass of Pb(CH3COO)2 = 207 + 2(12 + 3 + 12 + 16 +16) = 207 + 2(59) = 207 + 118 = 325g
Mass of Pb(CH3COO)2 = 5g
Number of mole = Mass /Molar Mass
Number of mole of Pb(CH3COO)2 = 5/325 = 0.0154mole
From the equation,
1mole of Pb(CH3COO)2 produced 1mole of PbS.
Therefore, 0.0154mole of Pb(CH3COO)2 will also produce 0.0154mole of PbS
2. The name of the reaction is double displacement reaction since the ions in the two reactants interchange to form two different products
They are examples of physical<span> contaminants .</span>
