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yarga [219]
2 years ago
12

Calculate the pH of the 4M NaOH

Chemistry
2 answers:
kirill115 [55]2 years ago
8 0
Points pls pls pls points
krek1111 [17]2 years ago
3 0

\text{NaOH}(aq) \longrightarrow \text{Na}^{+} (aq)+ \text{OH}^{-}(aq)\\\\k_w = [\text{H}_3 \text{O}^{+}][\text{OH}^{-}]\\\\\implies 10^{-14} = [\text{H}_3 \text{O}^{+}] \cdot 4\\\\\implies   [\text{H}_3 \text{O}^{+}]  = \dfrac{10^{-14}}4 = 2.5 \times 10^{-15}~ M\\\\\text{pH} = -\log[\text{H}_3 \text{O}^{+}] = -log(2.5 \times 10^{-15})=14.603

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azamat

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