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Liula [17]
3 years ago
8

How do I get this answer

Physics
1 answer:
Natalka [10]3 years ago
7 0

Steam.. Hope it helps...

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What is the application of a spherometer in the medical field?​
Anton [14]

Answer:

To correct the defects of vision by measuring the radius of curvature and thus the power of the lenses.

Explanation:

A spherometer is an instrument used to measure the curvature of objects such as lenses and curved mirrors.

Generally it consists of a fine screw which is moving in a nut carried on the center of a 3 small legged table or frame. The feet forms the vertices of an equilateral triangle. The lower end of the screw and those of the table legs are finely tapered and terminate in hemispheres.

If the screw has two turns of the thread to the milli meter the head is generally divided into 50 equal parts, so that differences of 0.01 millimeter may be measured without using a vernier scale.

The spherometer is used to measure the radius of curvature of the lenses so that the opthalmologist find the focal length of the lens and then give the  power to the lens to correct the defects of vision.  

8 0
3 years ago
Consider a resistor (R=1000 kΩ) and a capacitor (C=1μF) connected in series. This configuration is connected in series to a batt
BabaBlast [244]

Answer:

The maximum pressure is 10 V from across condenser.The highest charge mostly on condenser. 
Vc  = 10 x 1mf

= 10 ^ - 5C

The time it takes for the condenser to be 5 V different.        
Thus we have, 0.69 x 10 ^ - 3 seconds.

5 0
2 years ago
A car accelerates uniformly at 2m/s2 for 3minutes. what is the velocity of the car​
grigory [225]

Answer:

56.7 nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

4 0
4 years ago
Convert 1215 m to km.<br> Answer:
IgorC [24]

Answer:

it is 12.15 km

Explanation:

1215 km ÷1000

=12.15

please mark as brainliest

8 0
3 years ago
if you have a block of steel with a density of 7.8g/cm3 and a block of gold with a density of 19.3g/cm3 each with the same volum
natita [175]
Gold because 19.3 is greater than 7.8
3 0
3 years ago
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