A car accelerates uniformly at 2m/s2 for 3minutes. what is the velocity of the car

For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N, where t is in seconds. If

KATRIN_1 [288]

Answer:

15.6m/s

Completed Question;

For a short period of time, the frictional driving force acting on the wheels of the 2.5-Mg van is N= 600t^2 , where t is in seconds. If the van has a speed of 20 km/h when t = 0, determine its speed when t = 5

Explanation:

Mass m = 2500kg

Speed v1 = 20km/h = 20/3.6 m/s = 5.556 m/s

To determine speed v2;

Using the principle of momentum and impulse;

mv1 + ∫₀⁵ F dt = mv2

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Chuge%20%5Csf%E0%BC%86%20%5C%3A%20%20question%20%20%5C%3A%20%E0%BC%84" id="TexFormula1" titl

Montano1993 [528]

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards.

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.Let the common acceleration = a m/s^2

Man: net force = T - f = m a = 50 a 

net force = T - f = m a = 50 a 

Plank: net force = T + f = m a = 100 a

net force = T - f = m a = 50 a 

Plank: net force = T + f = m a = 100 a

As T = 100 N, a = 4/3 m/s^2 and f = 100/3 Newtons. 

[correct me if I'm wrong]:)

6 0

3 years ago

Read 2 more answers

1. What would cause a wave to travel at a different speed?

kvv77 [185]

Answer:

1 going from a gas to a liquid

2 longitudinal waves

3 longitudinal waves

4 transverse waves

3 0

3 years ago

A car with a velocity of 22 m/s is accelerated at a rate of 1.6m/s2 for 6.8s. determine the final velocity

Ivahew [28]

A car with a velocity of 22 m/s is accelerated at a rate of 1.6 $m/s^2$ for 6.8s has the final velocity t be 32.88 m/s.

The acceleration means the amount of velocity changing per unit time.

The given data:

initial velocity, u = 22 m/s

time, t = 6.8 s

acceleration, a = 1.6 $m/s^2$

We will be using the equation of motion:

v = u + at

$\therefore v=22+1.(6.8)$

$\Rightarrow v=22+10.88$

$\Rightarrow v=32.88 \ m/s$

The final velocity become 32.88 m/s.

To learn more about Attention here:

https://brainly.in/question/10557838

#SPJ4

3 0

2 years ago

On December 26, 2004, a violent earthquake of magnitude 9.1 occurred off the coast of Sumatra. This quake triggered a huge tsuna

Sonja [21]

Answer:

a) 800 km

b) 9.79° & 12.47°

Explanation:

It is known that the wavelength of any material or substance is given by the relation 入 = v/f

From the question, the time between the crest is given as 1.0 h, therefore, t = 1.0 h

Also, remember that frequency, f can be represented by

f = 1/t, and thus,

f = 1/1.0 h = 1.0 h^-1. This is our frequency, and would be used in the primary stated formula

入 = v/f, from the question, the speed is already stated as 800 km/h, so we apply directly

入 = 800 / 1

入 = 800 km. Therefore, the wavelength of the tsunami is 800 km

B,

the smallest angle between the Southern tip of Africa is

Sinθ = 800 / 4500

Sinθ = 0.17

θ = Sin^-1 0.17

θ = 9.79°

The smallest angle between the Southern end of Australia is

Sinθ = 800 / 3700

Sinθ = 0.216

θ = Sin^-1 0.216

θ = 12.47°

4 0

4 years ago

A car accelerates uniformly at 2m/s2 for 3minutes. what is the velocity of the car​

A car accelerates uniformly at 2m/s2 for 3minutes. what is the velocity of the car