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4 years ago

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Sound travels at a rate of 340 m/s in all directions through air. Matt rings a very loud bell at one location, and Steve hears i

t some time later at his location 450 meters to the south. How long did it take the sound to travel from the bell to Steve’s location?

1 answer:

Mice21 [21]4 years ago

5 0

It took 450/340 = 1.32 seconds

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20.0 moles, 1840 g, of a nonvolatile solute, C 3H 8O 3 is added to a flask with an unknown amount of water and stirred. The solu

Anastasy [175]

Answer:

0.144 kg of water

Explanation:

From Raoult's law,

Mole fraction of solvent = vapor pressure of solution ÷ vapor pressure of solvent = 423 mmHg ÷ 528.8 mmHg = 0.8

Let the moles of solvent (water) be y

Moles of solute (C3H8O3) = 2 mole

Total moles of solution = moles of solvent + moles of solute = (y + 2) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.8 = y/(y + 2)

y = 0.8(y + 2)

y = 0.8y + 1.6

y - 0.8y = 1.6

0.2y = 1.6

y = 1.6/0.2 = 8

Moles of solvent (water) = 8 mol

Mass of water = moles of water × MW = 8 mol × 18 g/mol = 144 g = 144/1000 = 0.144 kg

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3 years ago

Which most likely indicates a chemical change has occurred?

Marta_Voda [28]

A green liquid becoming a red liquid

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3 years ago

What are the coefficients in this expression?

skad [1K]

6 and $\frac{1}{3}$

Explanation:

The expression:

6a - $\frac{3}{4} + 7.5 - \frac{b}{3}$

A coefficient is a numerical constant usually placed before a variable in an expression.

They are used to multiply variables.

Given equation is;

$6a - \frac{3}{4} + 7.5 - \frac{b}{3}$

There are two variables in this expression which are;

a and - b

$6 (a) - \frac{3}{4} + 7.5 - b (\frac{1}{3} )$

The coefficients in this expression are:

6 and $\frac{1}{3}$

learn more:

Quadratic equation brainly.com/question/1357167

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7 0

3 years ago

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In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 50

dem82 [27]

Answer:

$0.1$ m

Explanation:

$d$ = slit width = 0.1 mm = 0.1 x 10⁻³ m

$\lambda$ = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

$D$ = Distance of the screen = 10 m

$w$ = Spacing between successive minima

Spacing between successive minima is given as

$w = \frac{2D\lambda }{d}$

Inserting the values given

$w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}$

$w = 0.1$ m

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3 years ago

A hockey puck slides off the edge of a platform with an initial velocity of 20 m/s horizontally. The height of the platform abov

Rina8888 [55]

Answer:

20.96 m/s

Explanation:

Using the equations of motion

y = uᵧt + gt²/2

Since the puck slides off horizontally,

uᵧ = vertical component of the initial velocity of the puck = 0 m/s

y = vertical height of the platform = 2 m

g = 9.8 m/s²

t = time of flight of the puck = ?

2 = (0)(t) + 9.8 t²/2

4.9t² = 2

t = 0.639 s

For the horizontal component of the motion

x = uₓt + gt²/2

x = horizontal distance covered by the puck

uₓ = horizontal component of the initial velocity = 20 m/s

g = 0 m/s² as there's no acceleration component in the x-direction

t = 0.639 s

x = (20 × 0.639) + (0 × 0.639²/2) = 12.78 m

For the final velocity, we'll calculate the horizontal and vertical components

vₓ² = uₓ² + 2gx

g = 0 m/s²

vₓ = uₓ = 20 m/s

Vertical component

vᵧ² = uᵧ² + 2gy

vᵧ² = 0 + 2×9.8×2

vᵧ = 6.26 m/s

vₓ = 20 m/s, vᵧ = 6.26 m/s

Magnitude of the velocity = √(20² + 6.26²) = 20.96 m/s

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3 years ago

Read 2 more answers