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Ede4ka [16]
2 years ago
14

These are the types of attractions found between molecules. Their strength determines the state of the substance at room tempera

ture
Physics
1 answer:
VLD [36.1K]2 years ago
5 0

Answer:

Intermolecular forces

Explanation:

The force of attractions that act between molecules are called intermolecular forces.

Their nature is electromagnetic, this means that they are just an expression of the electromagnetic force.

One example of intermolecular force is the ionic bond: this type of bond occurs when there are two ions, one positively charged and the other one negatively charged, and they are attracted by each other due to the electrostatic force, which therefore creates a bond between them.

Other types of intermolecular forces include:

Hydrogen bond

Ion-dipole forces

Van der Waals forces

The strength of these intermolecular forces determine the state of the substance. In fact, in solids, these forces are very strong, so that the molecules are strongly bond to each other and they cannot move freely, but only vibrate about their fixed position. On the other hand, in gases, these forces are very weak, therefore the molecules are able to move freely away from each other.

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Mrs. Smith does her daily chores. She walks 5 m to the laundry room and then turns around and walks -14 m to the kitchen. The wh
Nesterboy [21]

Answer:

Explanation:

Velocity vs speed and distance vs displacement is a pretty important.  Distance and speed have no direction while displacement and velocity have a direction.

In other words, taking the first example, going 5m one way and then 14 the other would make the total distance 19m, while displacement would be -9m from where you started.  

Anyway, velocity is displacement divided by time.  For the first one I already got that the displacement is -9m, and the time is 11 minutes.  It's worth noting that the answers are all in m/s, so we should convert the minutes to seconds.  To do that multiply 11 minutes by (60 seconds/1 minute) so the minutes cancel out.  so 11*60 is 660 seconds.  Now, to find velocity we just divide.  -9m/660s = -.0136 Which... doesn't seem to be one of the options...

For the second part it gives two point of views.  If you were standing on the carrier, the spy would look like it was moving  4 m/s away from you, but the carrier itself is moving 12 m/s in the positive direction to an onlooker.  If it's hard to figure out try thinking what it would look like if the spy was just standing still.  it would look like they were moving -12 m/s if you were standing on the carrier.  Then if the spy was moving at say 1 m/s it would look like they were moving -11 m/s if you were standing on the carrier.  

Just keep that line of reasoning , where if it looks like the spy is moving -4 m/s from the carrier then the spy is moving 4 m/s slower than the carrier, so the spy is moving at 8 m/s

Pretty sure I got the first part right, so maybe a misprint from the question?

8 0
3 years ago
Billy drops a ball from a height of 1 m. The ball bounces back to a height of 0.8 m, then
Andreas93 [3]

Answer:

The displacement is  \Delta H =    -  1 \ m

The distance  is  D =  4 \  m

Explanation:

From  the question we are told that

    The height from which the ball is dropped is  h  =  1 \ m

    The height attained at  the first bounce is  h_1  = 0.8  \  m

    The height attained at  the second bounce is   h_2 = 0.5 \  m

    The height attained at  the third bounce is h_3 = 0.2 \  m

Note  : When calculating displacement we consider the direction of motion

Generally given that upward is positive  the total displacement of the ball is mathematically represented as

            \Delta H =  (0  -  h ) + ( h_1 - h_1 ) + (h_2 - h_2 )+ (h_3 - h_3)

Here the 0 show that there was no bounce back to the point where Billy released the ball  

           \Delta H =  (0  -  1 ) + ( 0.8- 0.8 ) + (0.5 - 0.5 )+ (0.2 - 0.2)

=>          \Delta H =    -  1 \ m

Generally the distance covered by the ball is mathematically represented as  

                D =  h +  2h_2 + 2h_3 + 2h_3

The 2 shows that the ball traveled the height two times

              D =  1 +  2* 0.8  + 2* 0.5 + 2* 0.2

=>           D =  4 \  m

     

5 0
3 years ago
(WILL MARK BRAINLIEST and 27pts) What is the formula used to calculate the distance to an object in parsecs
Eduardwww [97]

Answer:

a. d=1/p

Explanation:

The simple formula for calculating the distance to an object in parsecs is to divide 1 by the number of parsecs to find the distance in light years. Hope this helps!

7 0
3 years ago
Read 2 more answers
Wts the average velocity​
Alexeev081 [22]

Answer:

2.11 m/s

Explanation:

V=disp/time

V=(0.52m+3.7m)/(2)

V=4.22/2

V=2.11 m/s

5 0
3 years ago
A projectile lands at the same height from which it was launched. which initial velocity will result
Serhud [2]

The required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

First, we must understand that the component of the velocity along the vertical is due to maximum height achieved and expressed as usin θ.

The component of the velocity along the horizontal is due to the range of the object and is expressed as ucosθ.

If the <u>air resistance is ignored</u>, the velocity of the object will be constant throughout the flight and the initial velocity will be equal to the final velocity.

Hence the required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

Learn more here; brainly.com/question/12870645

5 0
3 years ago
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