Answer:
d. A projectile with a horizontal component of motion will have a constant horizontal velocity.
f. The horizontal velocity of a projectile is unaffected by the vertical velocity; these two components of motion are independent of each other.
g. The horizontal displacement of a projectile is dependent upon the time of flight and the initial horizontal velocity.
h. The final horizontal velocity of a projectile is always equal to the initial horizontal velocity.
Explanation:
When we are dealing with parabolic motion, the x-component of the velocity remains the same (hence, in the case of the horizontal component, the acceleration will always be zero), <u>while the y-component always change because it is affected by the acceleration due gravity that acts verticaly.</u>
On the other hand, the horizontal displacement 
of the projectile is mathematically expressed as:
Where:
is the projectile's horizontal component of the initial velocity
is the time the parabolic motion lasts
This means <u>the projectile's horizontal displacement is directly proportional to the horizontal component of the initial velocity and the total time the projectile describes the parabolic motion</u>.
Of course, all of this considerations are assuming this is an ideal parabolic path and there is no air resistance.
Answer:
Into the page
Explanation:
According to Fleming's hand rule, the middle finger represent the direction of the current, the forefinger represents that of the magnetic field and the thumb gives the direction of the force. when you hold out your left hand with the forefinger, middle finger and thumb at the right angle to one another as the thumb points upward the middle finger will point rightward and the forefinger will point in the direction into the paper.
Death. The sun went out the plants would start to die, trees will die, out trees there won’t be oxygen. So everything would die
Answer:
Increases....because you get closer to the core :)
Answer:
A.) 1430 metres
B.) 80 seconds
Explanation:
Given that the train accelerates from rest at 1.1m/s^2 for 20s. The initial velocity U will be:
U = acceleration × time
U = 1.1 × 20 = 22 m/s
It then proceeds at constant speed for 1100 m
Then, time t will be
Time = distance/ velocity
Time = 1100/22
Time = 50 s
before slowing down at 2.2m/s^2 until it stops at the station.
Deceleration = velocity/time
2.2 = 22/t
t = 22/2.2
t = 10s
Using area under the graph, the distance between the two stations will be :
(1/2 × 22 × 20) + 1100 + (1/2 × 22 × 10)
220 + 1100 + 110
1430 m
The time taken between the two stations will be
20 + 50 + 10 = 80 seconds
