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tekilochka [14]
3 years ago
8

A 50kg girl is playing soccer. She runs towards the ball at a speed of 7 m/s. How much kinetic energy does she have as she runs

Physics
2 answers:
stepladder [879]3 years ago
6 0
Yup its 1,225j thank you lol i need more wordsssssss

stepladder [879]3 years ago
3 0
The calculation for kinetic energy is this

KE = 1/2mv^2

KE = 1/2(50)(7^2)

KE = 1/2(49•50)

KE = 1225 kgm^2/s^2.

Or simply 1225 J.

She possess this much energy when she runs.
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The SAF operates the M113 Ultra APC.
HACTEHA [7]

The volume of the object must be no larger than 11.15 m^3.

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

\rho = 1000 kg/m^3

This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

\rho = \frac{m}{V}

where

m is the mass of the object

V is its volume

For the object in this problem, the mass is

m=1.115\cdot 10^4 kg

Therefore, we can re-arrange the equation to find its volume:

V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3

So, the volume of the object must be no larger than 11.15 m^3.

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

8 0
3 years ago
Help me pleaseeee I will give you 42 points!<br> (I am dumb so that’s why)
Anit [1.1K]
Search each one of them up on GOOGLE it’s easier trust me
7 0
3 years ago
Read 2 more answers
When it reacts with another element, an oxygen atom gains two electrons.
luda_lava [24]

Answer:

A

Explanation:

An ion with a negative charge

3 0
3 years ago
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Mathphys Help help help
Keith_Richards [23]

Answer:

1030 mph

Explanation:

The new velocity equals the initial velocity plus the wind velocity.

First, in the x (east) direction:

vₓ = 335 mph + 711 cos 19° mph

vₓ = 1007 mph

And in the y (north) direction:

vᵧ = 0 mph + 711 sin 19° mph

vᵧ = 231 mph

The net speed can be found with Pythagorean theorem:

v² = vₓ² + vᵧ²

v² = (1007 mph)² + (231 mph)²

v ≈ 1030 mph

6 0
3 years ago
Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
Troyanec [42]

Answer:

The lowest possible frequency of sound is 971.4 Hz.

Explanation:

Given that,

Distance between  loudspeakers = 2.00 m

Height = 5.50 m

Sound speed = 340 m/s

We need to calculate the distance

Using Pythagorean theorem

AC^2=AB^2+BC^2

AC^2=2.00^2+5.50^2

AC=\sqrt{(2.00^2+5.50^2)}

AC=5.85\ m

We need to calculate the path difference

Using formula of path difference

\Delta x=AC-BC

Put the value into the formula

\Delta x=5.85-5.50

\Delta x=0.35\ m

We need to calculate the lowest possible frequency of sound

Using formula of frequency

f=\dfrac{nv}{\Delta x}

Put the value into the formula

f=\dfrac{1\times340}{0.35}

f=971.4\ Hz

Hence, The lowest possible frequency of sound is 971.4 Hz.

8 0
3 years ago
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