Explanation:
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Answer:
E=hf
Were, h = Planck constant 6.67*10^11
E=3.8*10^24 * 6.67*10^11= 2.508*q0^36j
Answer:
5900J
Explanation:
Work=Forse*Distance
work = J, Jewls
100*59=5900
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Find refractive index first



Now






Answer:
1.11 V
Explanation:
Given that the Einstein photoelectric equation states that;
KE = E - Wo
E = energy of incident photon
Wo= work function of the metal
E = hf = 6.64 x 10-34 * 6 x 1014
E = 39.84 * 10^-20 J or 3.98 * 10^-19 J
KE = 3.98 * 10^-19 J - 2.2 x 10-19J
KE = 1.78 * 10^-19J
We convert this value of KE to electron volts
KE = 1.78 * 10^-19J/1.6 x 10-19C
KE = 1.11 eV
Hence; 1.11 V will be just sufficient to stop electrons emitted by the sodium photo-plate reaching the collector plate.