<h3>Porque deja de funcionar una estufa electrica cuando la electricidad es excesiva?</h3>
- Es normal que los quemadores superiores de una estufa eléctrica o una estufa se enciendan y apaguen en configuraciones distintas a Hi. El quemador se encenderá y apagará más de lo normal cuando se utilizan cacerolas que no son planas o que son del tamaño incorrecto para el quemador.
<h2>☆彡Hanna</h2>
#CarryOnLearning
Answer:37 J
Explanation:
Given
Step :1
Heat added Q=44 J
Work done=-20 J

Step :2
Heat added Q=-61 J
work done 



as the process is cyclic


work done in compression is 37 J
Answer:
(4xy+5ab)(4xy-5ab)
Explanation:
16
-25

4^2 is 16 and 5^2 is 25,
Also, (x-a)(x+a) = x^2-a^2
So, this factorized is:
(4xy+5ab)(4xy-5ab)
Hope this helps!
Answer:
(a) surface area of the plate will be equal to 
(b) Charge on the capacitor is equal to 
Explanation:
We have given spacing between the plates d = 0.05 mm = 
Value of capacitance 
(A) Capacitance of a parallel plate capacitor is equal to 
So 

So surface area of the plate will be equal to 
(B) It is given that capacitor is charged by 1.5 volt
So voltage V = 1.5 volt
Charge on the capacitor is equal to 
So 
Answer:
d. zero
Explanation:
Constant velocity means the acceleration is zero. In this case the velocity does not change,
hope this helps you
have a good day :)