All categories

2 years ago

If a problem says an object has a

Physics

1 answer:

gtnhenbr [62]2 years ago

5 0

Answer:

Acceleration = 0

Explanation:

Initial velocity is the speed it starts going at. Final velocity is how fast it's going by the end. The acceleration is what changes the velocity. But if the acceleration is 0, the velocity will not change

You might be interested in

If water is leaking from a certain tank at a constant rate, is it leaking at a rate that is greater than 12 liters per hour?(1 l

Margarita [4]

Answer:

Yes it is possible because 3.33 is greater than 2.

Explanation:

Given that,

1 liter = 1000 milliliters

Suppose water is leaking from the tank at a rate that is greater than 2 milliliters per second.

We need to change the unit in ml/s

$12 lit/hr=\dfrac{12000}{3600}$

$12 lit/hr=3.33\ ml/s$

Hence, Yes it is possible because 3.33 is greater than 2.

5 0

3 years ago

A gravitational field is generated by any object that has

WITCHER [35]

Answer:

two poles

Explanation:

5 0

3 years ago

Read 2 more answers

If the pressure of a gas sample is quadrupled and the absolute temperature is doubled. True or False

Vanyuwa [196]

The given statement"If the pressure of a gas sample is quadrupled and the absolute temperature is doubled" is false.

Answer: Option B

<u>Explanation:</u>

As we know the direct relationship between Pressure and Temperature by the Gay-Lussac’s Law,

$P_{1} T_{1}=P_{2} T_{2}$

From this, we get,

$\frac{P_{1}}{T_{2}}=\frac{P_{2}}{T_{1}}$

$T_{2}=\frac{P_{1} T_{1}}{P_{2}}$

So, according to given statement, we have $P_{2} = 4 P_{1}$

Then from the above expression, we can find out the value of $T_{2}$ when pressure increased by 4 times of initial pressure as,

$T_{2}=\frac{P_{1} T_{1}}{4 P_{1}}$

Hence, we get,

$T_{1}=4 T_{2}$

Hence, from the above expression we can say that as we increase the pressure four times, the temperature does not get doubled. So, the given statement in the question is false.

6 0

4 years ago

Two long parallel wires are separated by 6.0 mm. The current in one of the wires is twice the other current. If the magnitude of

lions [1.4K]

Answer:

Explanation:

Magnitude of force per unit length of wire on each of wires

= μ₀ x 2 i₁ x i₂ / 4π r where i₁ and i₂ are current in the two wires , r is distance between the two and μ₀ is permeability .

Putting the values ,

force per unit length = 10⁻⁷ x 2 x i x 2i / ( 6 x 10⁻³ )

= .67 i² x 10⁻⁴

force on 3 m length

= 3 x .67 x 10⁻⁴ i²

Given ,

8 x 10⁻⁶ = 3 x .67 x 10⁻⁴ i²

i² = 3.98 x 10⁻²

i = 1.995 x 10⁻¹

= .1995

= 0.2 A approx .

2 i = .4 A Ans .

6 0

4 years ago

A 9 m3 container is filled with 300 kg of r-134a at 10°c. what is the specific enthalpy (kj/kg) of the r-134a in the container?

andreev551 [17]

Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg

8 0

3 years ago