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taurus [48]
3 years ago
13

A group of electrons orbiting at roughly the same distance from the nucleus

Chemistry
2 answers:
REY [17]3 years ago
6 0
A shell of electrons.

Ber [7]3 years ago
6 0
Yes and...
so what is ur question ?
plz here on brainly u ask questions not a place to practice writing fragments
and plz don't erase this! thanks u
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Please help me this is an easy science question where you put the correct lettered answer in the small chart. Please help you ge
Elanso [62]
Where is the picture? And the question?
4 0
3 years ago
Which two reactants make Calcium carbonate?
Norma-Jean [14]

Impossible to form from given reactants

Explanation:

Only sodium has carbonate ion here .so only possible way to displace carbonate is to use potassium

When sodium carbonate and Potassium iodide react with each other double displacement reaction occurs

As potassium is powerful than sodium it displaces sodium to form potassium carbonate .

Then you have to use water and then you can use calcium suppliment .

3 0
1 year ago
Read 2 more answers
How many formula units make up 25.8g of magnesium chloride (MgCl2)? Express the number of formula units numerically.
Verdich [7]

Answer:

Explanation:

Kandndkjwnww

8 0
3 years ago
What is the value of for this aqueous reaction at 298 K? <br><br>A+B↽⇀C+D ΔG°=12.86 kJ/mol<br><br>K=
agasfer [191]

Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

<em>Where ΔG is Gibbs free energy = 12.86kJ/mol</em>

<em>R is gas constant = 8.314x10⁻³kJ/molK</em>

<em>T is absolute temperature = 298K</em>

<em>And K is equilibrium constant.</em>

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

<h3>The equilbrium constant is 179.6</h3>

8 0
3 years ago
Which of the following statements is not correct?
velikii [3]
To answer the question above, multiply the given number of moles by the molar masses.

(A)     (0.20 mole) x (32 g / 1 mole) = 6.4 grams O2
(B)     (0.75 mole) x (62 g / 1 mole) = 46.5 grams H2CO3
(C)     (3.42 moles) x (28 g / 1 mole) = 95.7 grams CO
(D)     (4.1 moles) x (29.88 g / 1 mole) = 122.508 g Li2O

The answer to the question above is letter D.
4 0
3 years ago
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