Answer:
Explanation:
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In this case, according to the given chemical reaction, it is first necessary to compute the moles of reacting LiOH given its molar mass:
Thus, since there is a 1:1 mole ratio between lithium hydroxide and silver nitrate (169.87 g/mol) the resulting milligrams turn out to be:
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Yes, it would be the last one as the zeros that appear after a non zero number are significant.
Element:- Gold.
Compound:- Sodium Chloride (NaCl).
Ion: an atom that has lost or gained an electron.
Isotopes:- two atoms of hydrogen, each with a different number of neutrons
Cation:- an atom that has developed a positive charge.
Anion: an atom that has gained a negative charge
Answer:
Explanation:
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
Given:
75 % is decomposed which means that 0.75 of is decomposed. So,
![\frac {[A_t]}{[A_0]}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D)
= 1 - 0.75 = 0.25
t = 60 min
![\frac {[A_t]}{[A_0]}=e^{-k\times t}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%3De%5E%7B-k%5Ctimes%20t%7D)
k = 0.023 min⁻¹
Considering the expression for half life as:-
Where, k is rate constant
So,
<u>Answer</u>:
mass of magnesium oxide is 4.2 grams.
<u>Explanation</u>:
Balanced equation: 2Mg + O2 → 2MgO.
Given that 2.5 g Mg reacts with 3.0 g O2
- mass = moles * Mr
- moles = mass/Mr
- Mr = mass/moles
First find the moles of Mg:
moles = mass/Mr
moles = 2.5/ 24
moles = 0.104 moles
Using molar ratio, magnesium oxide will have same moles as Mg as they both have "2" molar ratio. So moles of Mg is 0.104 moles.
mass = moles * Mr
mass = 0.104 * 40
mass - 4.1667 g
mass = 4.2 g ___________this is the mass of MgO
