To answer this item, it is assumed that O2 is an ideal gas such that it follows the ideal gas law.
PV = nRT
Solving for n,
n = PV / RT
where n is number of moles, P is pressure, V is volume, R is the universal gas constant, T is the temperature.
Substituting the known values,
n = (724 mmHg/760 mmHg/1 atm)(1 L) / (0.0821 L. atm/mol.K)(298 K)
Simplifying,
n = 0.0389
Hence, the value of n is 0.0389.
we have,
wavelenght=c/f
where c= 3×10^8 m/s
f=6.3×10^12 s^-1
so wavelength=(3×10^8)/(6.3×10^12)
=0.476×10^-4 m
Answer:
Valence electrons are the electrons in the highest occupied principal energy level of an atom.
Answer:
See below.
Explanation:
The mass of octane in the sample of gasoline is 0.02851 * 482.6 = 13.759 g of octane.
The balanced equation is:
2C8H18(l) + 25O2(g) ----> 16CO2(g) + 18H2O(g)
From the equation, using atomic masses:
228.29 g of octane forms 704 g of CO2 and 324.3 g of H2O
So the mass of CO2 formed from the combustion of 13.759 g of octane = (704 * 13.759) / 228.29
= 42.43 g of CO2.
Amount of water = 324.3 * 13.759) / 228.29
= 19.55 g of H2O.
Oxygen is an element, symbol O
Magnesium oxide is an ionic compound, formula MgO