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inysia [295]
3 years ago
11

A substance that dissolves another substance is a _____________________

Chemistry
2 answers:
Scorpion4ik [409]3 years ago
7 0

Answer:

b it is easy its b

Explanation:

balandron [24]3 years ago
5 0

Answer:

B

Explanation:

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Which type of society survives mainly by foraging for food?
Dennis_Churaev [7]
The appropriate answer is a. HUNTER-GATHERER. Hunter-gatherer societies are nomadic and they forage for edible plants, bean, fruits and nuts. They also hunt wild game for food. Early humans in the Neolithic period practiced this way of life. 
Agrarian societies thrive on agriculture which they depend on for sustainable and for trade. Animals and plants are domesticated and so people can settle and build a society. Pastoral agriculture is a semi-nomadic lifestyle where the society is centered around keeping herds of grazing animals. Industrial societies focus on manufacturing and this is the backbone of the society. 
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2 years ago
Mrs. Rushing fills a balloon with hydrogen gas to demonstrate its ability to burn. Which combination could she use to produce th
ale4655 [162]

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Mg and HCI

Explanation:

3 0
3 years ago
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Facing the wind. A) windward B) subaric C) monsoon D) biotic
SpyIntel [72]
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8 0
2 years ago
Inorganic chemicals: Select one:
natka813 [3]

Answer:

E

Explanation:

Inorganic chemicals are present both in ground and surface water. Inorganic chemicals are found in soil from which they may contaminate runoff and eventual find their way into surface water bodies. Also, inorganic ions may be leached into underground aquifers and contaminate or underground water .

5 0
3 years ago
The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process
tensa zangetsu [6.8K]

Answer: a) 1.7\times 10^{-4}

b) 3.4\times 10^{-4}

Explanation:

The reaction is :

2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Rate = Rate of disappearance of N_2O_5 = Rate of appearance of NO_2

Rate =  -\frac{d[N_2O_5]}{2dt} = \frac{d[NO_2]}{4dt}

Rate of disappearance of N_2O_5 = \frac{\text {change in concentration}}{time} = \frac{0.100-0.066}{200-0}=1.7\times 10^{-4}

a) Rate of disappearance of N_2O_5 = -\frac{d[N_2O_5]}{2dt}

Rate of appearance of NO_2 = \frac{d[NO_2]}{4dt}

b) Rate of appearance of NO_2 =  \frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}

8 0
2 years ago
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