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3 years ago

Which substance is an example of an element?

Chemistry

2 answers:

kaheart [24]3 years ago

6 0

It is B. I took the test!!

Gnoma [55]3 years ago

4 0

Copper is an element. An element is a substance that is entirely made from one type of atom.

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Balance the equation for ethane C3H6 burning in oxygen to form carbon dioxide and steam. _____C3H6 + ____ O2 ---> CO2 + ____H

aleksandrvk [35]

Answer:

2C3H6 + 9 O2 ---> 6 CO2 + 6 H2O

Explanation:

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2 years ago

Select all the correct locations.

NikAS [45]

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The land breeze arrow is correct

The rest are incorrect.

Warm air should 'rise' by the land

This air then moves towards the sea and cools down

The cool air would then sink

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5 0

3 years ago

Read 2 more answers

An allele whose trait shows up in an organism when the allele is present is a

dmitriy555 [2]

Dominant allele

Explanation:

An allele whose trait shows up in an organism when the allele is present is called a dominant allele.

An allele whose trait does not show up in an organism when present is called a recessive allele.

An allele is the two possible forms of gene.
A gene can be dominant or recessive in nature.
An allele is a DNA that occupies a particular locus on a chromosome.
They usually occur in pairs.
The allele determines hereditary characteristics.

Learn more:

Genetics brainly.com/question/10607948

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7 0

3 years ago

The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p

Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

$\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}$

(ii) Solve the relationship

Let x = mass of Al. Then

7.5 - x = mass of Fe

Moles of Al = x/27

Moles of Fe = (7.5 - x)/56

Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x /18

Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56

∴ x/18 + (7.5 - x)/56 = 0.2652

56x + 18(7.5 - x) = 267.3

56x + 135 - 18x = 267.3

38x = 132.3

x = 3.5 g

Mass of Al = 3.5 g

Mass of Fe = 7.5 g - 3.5 g = 4.0 g

The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

4 0

3 years ago

Carbon-14 naturally decays to carbon

barxatty [35]

Answer:

Carbon-14 naturally decays to Carbon-12

Explanation:

8 0

3 years ago

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