Answer:
Step-by-step explanation:
Let X be the no of customers who purchase atleast one item.
X is binomial since there are two outcomes and each customer is independent of the other.
a) Here n =10
Out of 10 customers we expect np = 3 customers to buy at least one item.
b) exactly 3 of the customers would purchase at least one item
=
c) the probability that no more than 3 customers would purchase at least one item
=
Answer:
23
Step-by-step explanation:
You need to draw a line of best fit, then extend the x-axis, but from inspection I think it is 23.
(19 is too low, 36 is too high)
Multiply the $0.95 by .06 or if you have a percentage button then do $0.95 by 60% and you’ll get your answer of 0.57
C= chair cost
t= table cost
Create two equations with the given information. Solve for one variable in equation one. Substitute that answer in equation two. Then you can solve for the needed information.
3c+2t=$18
5c+6t=$48
3c+2t=18
Subtract 2c from both sides
3c=18-2t
Divide both sides by 3
c=(18-2t)/3
Substitute the value for c in equation two:
5c+6t=$48
5((18-2t)/3)+6t=48
(90-10t)/3+6t=48
Multiply everything by 3 to eliminate fraction
(3)((90-10t)/3)+(3)(6t)=(3)(48)
90-10t+18t=144
90+8t=144
Subtract 90 from both sides
8t=54
Divide both sides by 8
t=$6.75 cost for table
Substitute the t value to solve for c:
3c+2t=18
3c+2(6.75)=18
3c+13.50=18
3c=4.50
c=$1.50 chair cost
Check:
5c+6t=$48
5(1.50)+6(6.75)=48
7.50+40.50=48
48=48
Hope this helps! :) If it does, please mark as brainliest.