2 years ago

Can someone pls help me on this

Chemistry

1 answer:

Sedbober [7]2 years ago

6 0

Answer:The bottom 3

Explanation:

Beacuse all of these have to do with this subject hope this helps.

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3 years ago

During region C of the graph above the energy being absorbed is a. increasing the velocity of the water particles. b. increasing

Mkey [24]

Answer:

Your answer would be B. Increasing the distance between the water molecules and increasing their phase energy.

Explanation:

Hope this helps you answer this question!

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2 years ago

How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?

meriva

Answer:

$\large \boxed{\text{77.4 mL}}$

Explanation:

Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

V/mL: 249

c/mol·L⁻¹: 0.0443 0.285

1. Calculate the moles of Ba(OH)₂

$\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}$

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

$\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}$

3. Calculate the volume of HCl

$V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}$

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3 years ago

Ulay the tiles to the correct boxes to complete the pairs. Not all tiles will be used

d1i1m1o1n [39]

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3 years ago

Someone help me pls ada

neonofarm [45]

I think the answer for #3 is A not 100% sure but hope I can help!

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2 years ago