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icang [17]
3 years ago
7

Experiment #1A melting point of an old sample of Naphthalene was completed and a melting range of 77-83 oC was observed and reco

rded. Complete the following calculations and show your work. 1. From the information and data in the JoVE video, calculate the percent error of the melting point compared to the literature value for the naphthalene sample.2. What does the melting point range and percent error suggest about the sample?
Chemistry
1 answer:
White raven [17]3 years ago
3 0

Answer:

%error = 0.32%

Explanation:

Let's answer both questions, by parts.

1. Percentage error:

In this case, I do not have the video, but I do have the reported melting point of naphtalene which is 80.26 °C.

The expression to calculate the percentage error is the following:

%Error = absolute error / actual percentage. (1)

And the absolute error is:

Abs error = actual value - experimental value  (2)

But the experimental value is a range, so we just have to get a average of that:

Exp value = 77 + 83 / 2 = 80 °C

Now the absolute error:

Abs error = 80.26 - 80 = 0.26 °C

Finally the %error:

%error = (0.26 / 80.26) * 100

<h2>%error = 0.32%</h2>

2. Meaning of melting point range and %error

The melting point range just means that the sample of naphtalene has impurities, and when a sample of any compound has impurities, melting point tends to be low. However, this decrease of temperature is a wider range. But usually a range of just 5° C means that compound has little traces of impurities but it can still be used for reactions.

The %error means that the impurities of the sample are really low, so the sample is practically pure with little traces of impurities.

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A 0.02 molar solution of sodium chloride contains 0.1 mole of solute. What is the volume of the solution
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Answer:

Volume of solution = 5 L

Explanation:

Given data:

Molarity of solution = 0.02 M

Moles of solute = 0.1 mol

Volume of solution = ?

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Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

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Molarity = number of moles of solute / L of solution

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3 0
2 years ago
What mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?
nikitadnepr [17]

The mass of water produced by the reaction of the 23 g of SiO_2  is 13.8 g.

The given chemical reaction;

4Hf (g)  \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)

In the given compound above, we can deduce the following;

  • molecular mass of SiO_2 = 28 + (2 x 16) = 60 g
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60 g of SiO_2  --------- 36 g of water

23 g of SiO_2  ------------- ? of water

mass \ of \ water = \frac{23 \times 36}{60} = 13.8 \ g \ of \ water

Thus, the mass of water produced by the reaction of the 23 g of SiO_2  is 13.8 g.

  • <em>"Your question is not complete, it seems to be missing the following information";</em>

In the reaction of the given compound, 4Hf (g)  \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l), what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

Learn more here:brainly.com/question/13644576

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`Let's just consider the concept of stoichiometry without any confusing chemicals. Here is a generic equation: 2A + 6B ? 3C. If
lesya [120]

Answer:

Option D. 5.5

Explanation:

The equation is this:

2A + 6B  ⇒  3C

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I have 11 B, so the limiting is B

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I have 4 A, so A is the excess.

6 B produce 3 C

11 B will produce ( 11 .3)/6 = 5.5C

7 0
3 years ago
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