Question

A 42.0g sample of a compound containing only C and H was analyzed. The results showed that the sample contained 36.0g of C and 6.0g of H. Which of the following questions about the compound can be answered using the results of the analysis?
A) What was the volume of the sample?
B) What is the molar mass of the compound?
C) What is the chemical stability of the compound?
D) What is the empirical formula of the compound?

Answer 1

Answer:

The correct answer is option D.

Explanation:

Mass of compound = 42.0 g

Mass of carbon in compound = 36.0 g

Mass of hydrogen in compound = 6.0 g

Moles of carbon = $\frac{36.0 g}{12 g/mol}=3.0 mol$

Moles of hydrogen = $\frac{6.0 g}{1 g/mol}=6.0 mol$

Empirical formula of the compound, divide least number of moles from each element.

Carbon = $\frac{3.0}{3.0}=1$

Hydrogen = $\frac{6.0}{3.0}=2$

Empirical formula of compound = $CH_2$

The empirical formula of the compound can be calculated from the given data.