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Darya [45]
2 years ago
5

A 42.0g sample of a compound containing only C and H was analyzed. The results showed that the sample contained 36.0g of C and 6

.0g of H. Which of the following questions about the compound can be answered using the results of the analysis?
A) What was the volume of the sample?
B) What is the molar mass of the compound?
C) What is the chemical stability of the compound?
D) What is the empirical formula of the compound?
Chemistry
1 answer:
SashulF [63]2 years ago
4 0

Answer:

The correct answer is option D.

Explanation:

Mass of compound = 42.0 g

Mass of carbon in compound = 36.0 g

Mass of hydrogen in compound = 6.0 g

Moles of carbon = \frac{36.0 g}{12 g/mol}=3.0 mol

Moles of hydrogen = \frac{6.0 g}{1 g/mol}=6.0 mol

Empirical formula of the compound, divide least number of moles from each element.

Carbon = \frac{3.0}{3.0}=1

Hydrogen = \frac{6.0}{3.0}=2

Empirical formula of compound = CH_2

The empirical formula of the compound can be calculated from the given data.

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2 years ago
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Answer:

B.

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3 years ago
The density of lava is 3.1 g/cm². It has a volume of 2700 cm3. How much does this block of lava weigh?
konstantin123 [22]

Answer:

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Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

density of lava = 3.1 g/cm³

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