1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
JulijaS [17]
3 years ago
15

How do the solvent and solute differ in a solution

Chemistry
1 answer:
hodyreva [135]3 years ago
7 0
A solution is a homogeneous mixture, meaning it contains 2 or more substances. A solute is a substance that’s dissolved in the solvent. Think of it as dissolving salt (solute) in water (solvent) to make a salt solution. The amount of each substance in the solution impacts the concentration of it. So if I put more salt than water, it increases its concentration, while adding more water decreases its concentration.
You might be interested in
Instructions
ivann1987 [24]

Answer:

I got a 100 with this, sorry if this is not what you want just trying to help

Explanation:

1. This experiment was to find how mass and speed effect KE. This is important because if you were in a situation where you needed something to go higher, you would know to add more or less of mass/speed.  

To test mass, we filled the bean bag with a certain amount of water, then dropped it. After, you recorded how high it made the bean bag go. The same with speed, but same amount in the bottle, just dropped from different heights.  

My hypothesis is when you have more mass, the KE will be greater. This is also the same with speed, if it is dropped from a higher place, the bean bag will launch farther than the last time.  

2. Data I collected from the lab was like my hypothesis explained. When the height of the bottle increased, it made the bean bag go higher than the last. And I tested 4 different masses, 0.125 kg, 0.250kg, 0.375kg and 0.500kg. Each time the bean bag went higher on a larger mass.  

A lot of times on the speed test, the bean bag would go higher than the bottle drop point, but not every time. Also, when it was dropped from the same height each time, some results varied quite a bit, like when it was dropped from 1.28 the results were 1.14 then 1.30 1.30. Mass on the other hand was all in the same number range, only once the numbers were a bit off from each other.  

3.  Some formulas I used were KE= ½ mv^2 and Ht v^2/2g. The first was to calculate the kinetic energy of an object, m=mass v=speed. Second was for finding out what height I needed to drop something to reach a certain speed, Ht=Height and g= Gravitational Acceleration of 9.8 m/s^2.  

I used these to figure out tables that showed relationships between different things like mass and KE or speed and height. The whole time I was doing the lab, my data was going up, when there was more mass/speed there were higher values in the table.  

This means that my hypothesis at the beginning was correct, more of m/s means KE will increase proportionally because they are all linear. I found it surprising when the bean bag height went over the water bottle drop mark.  

4.     To conclude, my hypothesis matched my data. The data values went up when more mass or speed was added. This means if I were in a situation where I needed more kinetic energy for something, I would know to increase mass or the speed of the object giving it energy.  

The reason that this hypothesis is correct is when you have more mass, you have more energy. So, when you drop let's say a baseball, it isn’t that heavy so it would only launch the bean bag so far. But a bowling ball is very heavy and has lots of energy when falling because of that, it would make the bean bag go very high.  

To make this experiment better, I would use a smoother material for the lever so energy wouldn’t be lost by friction from wood rubbing together. Also, maybe a scanner or video camera to more accurately record how far the bean bag went. All of these would help the lab get more precise results, maybe they could be used in a future lab.

8 0
3 years ago
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
3 years ago
To calculate acceleration you must know both the objects velocity and _______________ 1pt
KATRIN_1 [288]

Answer:

i think its speed

Explanation:

8 0
2 years ago
Read 2 more answers
The diagram below represents a sodium atom bonding to a chlorine atom to form sodium chlorine.
Sergio [31]
Sodium Chloride is a compound.
8 0
3 years ago
An element has an atomic number of 18 and an atomic mass of 40. The number of neutrons in the nucleus of an atom of this element
Vikentia [17]

Answer: 22 neutrons

Explanation: 40 is the mass number = atomic mass = total number of protons and neutrons in atomic nucleus

18 is the number of protons in the nucleus of this atom

Then 40 - 18 = 22 neutrons

and this is Argon

7 0
2 years ago
Other questions:
  • What is the most striking part of the Rutherford scattering stimulation?
    13·1 answer
  • Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ/mole) the standard enthalpy change DH° for
    13·2 answers
  • Given 40 grams of magnesium. How many mole is this
    5·1 answer
  • Watson and Crick worked out the structure of DNA molecules in 1952. This discovery affected the legal system that is used in soc
    5·2 answers
  • Approximate temperature of a .7 mold sample of a gas at 1.2 ATM and volume of .170 L
    10·1 answer
  • CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE
    6·1 answer
  • 1.Explain why the reactivity of group 7 decreases as you move down the group. Try to use the sentence starters here: When group
    8·1 answer
  • Which of the following statements about organelles is NOT true?
    12·2 answers
  • Please answerrrrrrrrrrrrrrrrrrrrrrrrr
    14·1 answer
  • Ignore the one I chose hehe! but please help?!
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!