The correct answer is amplitude
The charge of the object must be ![1.11 \times e^{-5} \text { coulomb }](https://tex.z-dn.net/?f=1.11%20%5Ctimes%20e%5E%7B-5%7D%20%5Ctext%20%7B%20coulomb%20%7D)
Answer: Option C
<u>Explanation:</u>
Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.
Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.
![Electric field, E=\frac{\text { Force }(F)}{q}](https://tex.z-dn.net/?f=Electric%20field%2C%20E%3D%5Cfrac%7B%5Ctext%20%7B%20Force%20%7D%28F%29%7D%7Bq%7D)
Here, given E = 4500 N/C and F = 0.05 N.
We need to find charge of the object (q)
By substituting the given values, we get
![q=\frac{F}{E}=\frac{0.05 N}{4500 \mathrm{N} / \mathrm{c}}=1.11 \times e^{-5} \text { coulomb }](https://tex.z-dn.net/?f=q%3D%5Cfrac%7BF%7D%7BE%7D%3D%5Cfrac%7B0.05%20N%7D%7B4500%20%5Cmathrm%7BN%7D%20%2F%20%5Cmathrm%7Bc%7D%7D%3D1.11%20%5Ctimes%20e%5E%7B-5%7D%20%5Ctext%20%7B%20coulomb%20%7D)
Answer:
A. Is the one that the experimenter manipulates directly
Explanation:
The independent variable is the one that is manipulated during an experiment by the experimenter.
The dependent variable is the one that is effected by the independent variable in an experiment.
Answer: 14 m/s
Explanation:
The speed
of a sound wave is given by the following equation:
Where:
is the wavelength of the sound wave
Hence:
Answer:
![7.2\cdot 10^{-19} J](https://tex.z-dn.net/?f=7.2%5Ccdot%2010%5E%7B-19%7D%20J)
Explanation:
The change in electrical potential energy of a charged particle moving through a potential difference is given by
![\Delta U = q \Delta V](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20q%20%5CDelta%20V)
where
q is the magnitude of the charge of the particle
is the potential difference
In this problem:
- the charge of the particle is 3.00 elementary charges, so
![q=3e=3\cdot 1.6\cdot 10^{-19} J=4.8\cdot 10^{-19}J](https://tex.z-dn.net/?f=q%3D3e%3D3%5Ccdot%201.6%5Ccdot%2010%5E%7B-19%7D%20J%3D4.8%5Ccdot%2010%5E%7B-19%7DJ)
- the potential difference is
![\Delta V=4.50 V](https://tex.z-dn.net/?f=%5CDelta%20V%3D4.50%20V)
So, the change in electrical potential energy is
![\Delta U=(1.6\cdot 10^{-19}C)(4.50 V)=7.2\cdot 10^{-19} J](https://tex.z-dn.net/?f=%5CDelta%20U%3D%281.6%5Ccdot%2010%5E%7B-19%7DC%29%284.50%20V%29%3D7.2%5Ccdot%2010%5E%7B-19%7D%20J)