Answer:
Work done by external force is given as
Explanation:
As per work energy Theorem we can say that work done by all force on the car is equal to change in kinetic energy of the car
so we will have
now we have
so from above equation
so from above equation work done by external force is given as
Answer:
The strength of the electric field is 2.258 x 10⁸ N/C
Explanation:
Potential energy = -p*ECosθ
where;
d is the dipole moment
E is the electric field
θ is the angle of inclination
→When the water molecules is perpendicular to the field, θ =90° and potential energy = p*ECosθ = d*ECos0 = 0
Total potential energy = 0 + 1.40×10⁻²¹J, since it is 1.40×10⁻²¹J more
→When the water molecules is aligned to the field, θ =0°
potential energy = -p*ECosθ
dipole moment, p = 6.2×10⁻³⁰Cm
= -(6.2×10⁻³⁰)*(E) Cos0
0 + 1.40×10⁻²¹ J = -(6.2×10⁻³⁰)*(E),
E = (1.40×10⁻²¹ J)/(6.2×10⁻³⁰)
E = 2.258 x 10⁸ N/C
Therefore, the strength of the electric field is 2.258 x 10⁸ N/C
Answer:
Explanation:
Initial velocity, u = 85 m/s
Final velocity, v = 45 m/s
Time, t = 4.5 s
We need to find the acceleration of the dragster. The rate at which the velocity of an object changes is called the acceleration of an object. It can be given by :
So, the acceleration of the dragster is and it is deaccelerating.
Answer:
(a) The magnitude of the electric dipole moment is 1.68 x 10⁻¹⁴ C.m
(b) The difference between the potential energies ΔU, is 4.6704 x 10⁻¹¹ J
Explanation:
Given;
magnitude of charge, q = 2 nC = 2 x 10⁻⁹ C
distance of separation, d = 8.4 μm = 8.4 x 10⁻⁶ m
strength of electric field, E = 1390 N/C
(a) the magnitude of the electric dipole moment
p = qd
p = (2 x 10⁻⁹ C)(8.4 x 10⁻⁶ m)
p = 1.68 x 10⁻¹⁴ C.m
(b) the difference between the potential energies for dipole orientations parallel and anti-parallel to E
ΔU = U(180) - U(0)
ΔU = 2pE
ΔU = 2(1.68 x 10⁻¹⁴ )(1390)
ΔU = 4.6704 x 10⁻¹¹ J