Find the equivalent resistance.
2 answers:
Answer:
18 Ω
Explanation:
As K and F are at the same voltage, we can redraw the diagram as in figure 2
Series resistances add directly, so we get figure 3
Adding parallel resistances gets us to figure 4
Now we can move two 6Ω resistances for clarification in figure 5
As the voltage between C and J will be identically split between D and H, there will be no voltage drop across the middle 6Ω resister and no current through it, identical to an infinite resistance, so that 6Ω can be eliminated as in figure 6
Add series resistances to get to figure 7
Add parallel resistances to get to figure 8
Add series resistances to get to figure 9
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A) 2.64t
B) 2.64h
C) 2.64D
Explanation:
A)
The motion of the athlete is equivalent to the motion of a projectile, which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion (constant acceleration) along the vertical direction
The time of flight of a projectile can be found from the equations of motion, and it is found to be
where
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the time of flight is .
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. Therefore, the time of flight on Mars will be:
B)
The maximum height reached by a projectile can be also found using the equations of motion, and it is given by
where
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the maximum height is .
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. So, the maximum height reached on Mars will be:
C)
The horizontal distance covered by a projectile is also found from the equations of motion, and it is given by
where:
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the horizontal distance covered is D.
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. Therefore, the horizontal distance reached on Mars will be: