Question

Calculate the final molarity of HCl the resulting solution when 5.56 mL of 4.108 M HCl is added to 4.44 mL of water.

Answer 1

The final molarity of HCl is 2.284 M

We'll begin by listing what was given from the question. This is shown below:

Initial volume (V₁) = 5.56 mL

Initial Molarity (M₁) = 4.108 M

Final volume (V₂) = 5.56 + 4.44 = 10 mL

Final Molarity (M₂) =?

The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

4.108 × 5.56 = M₂ × 10

22.84048 = M₂ × 10

Divide both side by 10

M₂ = 22.84048 / 10

M₂ = 2.284 M

Therefore, final molarity of the HCl solution is 2.284 M.

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