RTP: [a tan(u) + b]² + [b tan(u) - a]² = (a² + b²) sec²(u)
Proving LHS = RHS:
LHS = [a tan(u) + b]² + [b tan(u) - a]²
= a² tan²(u) + 2ab tan(u) + b² + b² tan²(u) - 2ab tan(u) + a²
= (a² + b²) tan²(u) + (a² + b²)
= (a² + b²)[tan²(u) + 1]
= (a² + b²) sec²(u), using the identity: tan²(x) + 1 = sec²(x)
= RHS
Answer:
Step-by-step explanation:
1) If you really meant X^2+12=40, then this simplifies to x^2 = 28, and therefore x = ±√28, or x = ±2√7.
2) If you meant X^2+12x=40:
a) Take half of the coefficient of x: that would be (1/2)(12), or 6.
b) Square this result, obtaining: 6² = 36
c) Add this 36 to x^2 + 12x + 40, and then subtract it: We get:
x² + 12x + 36 - 36 = 40, or x² + 12x + 36 = 76
We have to add 36, as indicated above, to "complete the square."
Answer:
english pls
Step-by-step explanation:
Answer:
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Step-by-step explanation:
X * 3^2 +2 = 47
X * 9 + 2 = 47
9X = 47 - 2
9x = 45
x = 45 : 9
X = 5

The required values are :
Length = 33 m
Breadth (width) = 30 m
solution is in attachment ~