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maks197457 [2]
3 years ago
8

What volume (in liters) of gasoline has a total heat of combustion equal to the energy obtained in part (a)? (see section 17.6;

the density of gasoline is 900 kg/m3.)?
Physics
1 answer:
antiseptic1488 [7]3 years ago
8 0
<h3><u>Answer;</u></h3>

volume = 6.3 × 10^-2 L

<h3><u>Explanation</u>;</h3>

Volume = mass/density

Mass = 0.0565 Kg,

Density = 900 kg/m³

             = 0.0565 kg/ 900 kg /m³

             = 6.3 × 10^-5 M³

but; 1000 L = 1 m³

Hence, <u>volume = 6.3 × 10^-2 L</u>

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A 2 kg melon is balanced on your bald uncle’s head. His son, Throckmorton, shoots a 50 g (0.05kg) arrow at it with a speed of 30
sineoko [7]

Answer:

The speed of the melon as it flies off the man’s head is 0.3 m/s.

Explanation:

Given;

mass of the melon, m₁ = 2 kg

initial speed of the melon, u₁ = 0

mass of arrow, m₂ = 0.05 kg

initial speed of the arrow, u₂ = 30 m/s

final speed of the arrow, v₂ = 18 m/s

let v₁ be the final speed of the melon as it flies off the man's head.

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

2(0) + 0.05 x 30 = 2v₁  + 0.05 x 18

1.5 = 2v₁ + 0.9

2v₁ = 1.5 - 0.9

2v₁ = 0.6

v₁ = 0.6 / 2

v₁ = 0.3 m/s

Therefore, the speed of the melon as it flies off the man’s head is 0.3 m/s.

4 0
3 years ago
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kirill [66]
An atom is a particle with a neutral charge
6 0
4 years ago
An object oscillates with an angular frequency of 8.0 rad/s. At t = 0, the object is at x0 = 4 cm with an initial velocity v0 =
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Answer:

\phi = 0.66 rad

A = 5.06 cm

Explanation:

We have here a simple harmonic motion, so the equation of the position in this motion is:  

x(t)=Acos(\omega t+\phi) (1)

A: Amplitude

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φ: phase constant

If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:

v(t)=\frac{dx(t)}{dt}=-A\omega sin(\omega t+\phi) (2)

Let's evaluate (1) and (2) in t=0.

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Dividing 4 by 3 we have:

\frac{v(0)}{x(0)}=-\omega tan(\phi)

\phi = tan^{-1}(\frac{-v(0)}{\omega x(0)})

\phi = 0.66 rad

Now, using (3) we can find the amplitude.

A = \frac{x(0)}{cos(\phi)} = 5.06 cm

I hope it helps!                            

6 0
4 years ago
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