1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irga5000 [103]
3 years ago
13

Marissa uses a cart to haul flowers at her job with a landscaper. She pushes a 12-kilogram cart a distance of 6 meters with a fo

rce of 25 Newtons. How much work does she do?
Physics
2 answers:
Inessa [10]3 years ago
6 0

Answer:

150 J.

Explanation:

Work-done: This can be defined as the product of force and distance moved along the direction of the force.

The S.I unit of work is Joules(J).

From the question,

W = F×d............. Equation 1

Where W = work done, F = force, d = distance.

Given: F = 25 N, d = 6 m

Substitute into equation 1

W = 25×6

W = 150 J.

Hence the work done by Marissa = 150 J

grandymaker [24]3 years ago
6 0

Answer:

150J

Explanation:

The following data were obtained from the question:

M (mass) = 12Kg

F (force) = 25N

d (distance) = 6m

w (work) =?

Work is defined as the product of force and distance moved in in the direction of the force. It is measured in joules and can be represented mathematically as:

work = force x distance

w = F x d

w = 25 x 6

w = 150J

Therefore, 150J of work is done

You might be interested in
Q: Riri wants to bake a cake. She adds flour, sugar, egg, baking soda, and yeast into a bowl and mixed them together. After all
babunello [35]

Answer:

I don't know what you mean about which changes occurred in this process but if its why the dough starts rising then its caused by the carbon dioxide in baking soda and yeast which is a fungus

8 0
3 years ago
Read 2 more answers
A box rests on top of a flat bed truck. The box has a mass of m = 16.0 kg. The coefficient of static friction between the box an
3241004551 [841]

Answer:

1) 1.31 m/s2

2) 20.92 N

3) 8.53 m/s2

4) 1.76 m/s2

5) -8.53 m/s2

Explanation:

1) As the box does not slide, the acceleration of the box (relative to ground) is the same as acceleration of the truck, which goes from 0 to 17m/s in 13 s

a = \frac{\Delta v}{\Delta t} = \frac{17 - 0}{13} = 1.31 m/s2

2)According to Newton 2nd law, the static frictional force that acting on the box (so it goes along with the truck), is the product of its mass and acceleration

F_s = am = 1.31*16 = 20.92 N

3) Let g = 9.81 m/s2. The maximum static friction that can hold the box is the product of its static coefficient and the normal force.

F_{\mu_s} = \mu_sN = mg\mu_s = 16*9.81*0.87 = 136.6N

So the maximum acceleration on the block is

a_{max} = F_{\mu_s} / m = 136.6 / 16 = 8.53 m/s^2

4)As the box slides, it is now subjected to kinetic friction, which is

F_{\mu_s} = mg\mu_k = 16*9.81*0.69 = 108.3 N

So if the acceleration of the truck it at the point where the box starts to slide, the force that acting on it must be at 136.6 N too. So the horizontal net force would be 136.6 - 108.3 = 28.25N. And the acceleration is

28.25 / 16 = 1.76 m/s2

5) Same as number 3), the maximum deceleration the truck can have without the box sliding is -8.53 m/s2

3 0
3 years ago
John says that the value of the function cos[ω(t + T) + ϕ], obtained one period T after time t, is greater than cos(ωt + ϕ) by 2
Svetllana [295]

Answer:

No one is right

Explanation:

John Case:

The function cos(\omega t +\phi) is defined between -1 and 1, So it is not possible obtain a value 2\pi greater.  

In addition, if you  move the function cosine a T Value, and T is the Period,  the function take the same value due to the cosine is a periodic function.

Larry case:

Is you have f=1+cos(\omega t +\phi), the domain of this is [0,2].

it is equivalent to adding 1 to the domain of the f=1+cos(\omega t +\phi), and its mean that the function f=cos(\omega t +\phi), in general, is not greater than cos(\omega t +\phi).

3 0
3 years ago
Imagine two billiard balls on a pool table. Ball A has a mass of 2 kilograms and ball B has a mass of 3 kilograms. The initial v
ratelena [41]
1. The balls move to the opposite direction but the same speed. This represents Newton's third law of motion.
2. The total momentum before and after the collision stays constant or is conserved.
3. If the masses were the same, the velocities of both balls after the collision would exchange.
4 and 5. Use momentum balance to solve for the final velocities.
8 0
3 years ago
Read 2 more answers
How big is the international space station?
oee [108]
The dimensions of the completed ISS research facility will be approximately 356 feet (109 meters) by 240 feet (73 meters), or slightly larger than a football field. the ISS weighes around 450 tons (408,000 kg), or 450 times the weight of an average car.
3 0
3 years ago
Other questions:
  • An airplane flies 21 km in 30 minutes. What is its average speed in kilometers per hour?
    10·2 answers
  • Please help with vectors (will give BRAINLIEST answer)
    7·1 answer
  • A bird can fly at 32 km/h. How long does it take to fly 22 km?​
    10·1 answer
  • Vector A has a magnitude of 16 m and makes an angle of 44° with the positive x axis. Vector B also has a magnitude of 13 m and i
    7·1 answer
  • The speed of a bullet of mass 20 g is 216 kilometre-per-hour what is kinetic energy in joules​
    13·1 answer
  • A 1000-turn toroid has a central radius of 4.2 cm and is carrying a current of 1.7 A. The magnitude of the magnetic field along
    5·1 answer
  • What are particles of carbon called?
    15·1 answer
  • Calculate the Reynolds number for a person swimming through maple syrup. The density of syrup is about 1400 kg/m^3 and the visco
    15·1 answer
  • What is work? how do we solve for work?​
    13·2 answers
  • Can you please answers these for me please today is the last day to turn in work and I need this to pass please I’m begging than
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!