List two things you should not do when encountering a funeral procession?

What apparatus is used to measure salt and water

AlexFokin [52]

Answer:

Salinometer, also called salinimeter or salimeter, device used to measure the salinity of a solution. It is frequently a hydrometer that is specially calibrated to read out the percentage of salt in a solution.

Explanation:

I hope it is correct answer

7 0

2 years ago

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What was Laurentia and what lands was it composed of? What happened to it?

snow_lady [41]

Laurentia, also called the North American Craton, is a huge continental craton. It forms the ancient geological core of the continent of North America. It is made up of present day North America and Greenland. About 300 million years ago, it collided with the southern hemispheric continent of Gondwana and formed the supercontinent called Pangaea.

4 0

3 years ago

Blocks A (mass 3.50 kg) and B (mass 6.50 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block

Vedmedyk [2.9K]

Answer:

(a) V (A) = 0.7 m/s,

(b) V (A) = 0.7 m/s,

(c) V (B) = 0.7 m/s

(d) u= - 0.60 m/s

(e) v = 0.75 m/s

Explanation:

Given:

M(A) =3.50 Kg, M(B)=6.50 Kg, V(A) = 2.00 m/s, V(B) = 0 m/s

Sol:

a) law of conservation of momentum

M(a) x V(A) + M(B) x V(B) = ( M(a) + M(B) ) V (let V is Common Velocity of Both block)

so 3.50 Kg x 2.00 m/s + 6.50 Kg x 0 m/s = (3.50 Kg + 6.50 Kg ) V

after solving V = 0.7 m/s

After the collision the velocities of the both block will be as the the spring is compressed maximum.

V (A) = 0.7 m/s

b) V(A) = 0.7 m/s ( Part (a) and Part (a) are repeated )

c) as stated above the in the Part (a)

V(B) = 0.7 m/s

d) When the both blocks moved apart after the collision:

Let u=velocity of block A after the collision.

and v = velocity of block B after the collision.

then conservation of momentum

M(a) x V(A) + M(B) x V(B) = M(a) x v + M(B) x u

⇒ 3.50 Kg x 2.00 m/s + 6.50 Kg x 0 m/s = 3.50 Kg x u + 6.50 Kg x v

⇒ 2.00 m/s = u + 1.86 v -----eqn (1) ( dividing both side by 3.50 Kg)

For elastic collision

the velocity relative approach = velocity relative separation

so 2.00 m/s = v-u ----- eqn (2)

⇒v = u + 2.00 m/s

putting this value in eqn (1) we get

2.00 m/s = u + 1.86 (v + 2.00 m/s)

u= - 0.60 m/s

e) putting v= 2.00 m/s in eqn (1)

2.00 m/s = - 2.32 m/s + 1.86 v

v = 0.75 m/s

5 0

3 years ago

6. The petrol in a petrol can weighs 2000g. The density of petrol is 0.8g/cm3.

frez [133]

Answer:

a. 2500 cm³.

b. 2.5 litres.

Explanation:

Given the following data:

Density = 0.8g/cm³

Mass = 2000g

To find the volume of the petrol;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

$Density = \frac{mass}{volume}$

Making volume the subject of formula, we have;

$Volume = \frac{mass}{density}$

Substituting into the equation, we have:

$Volume = \frac{2000}{0.8}$

Volume = 2500 cm³

a. The volume of the petrol in the can in cubic centimeters (cm³) is 2000.

b. The volume of the petrol in the can in litres;

1000 cm³ = 1 litre

2500 cm³ = x litres

Cross-multiplying, we have;

1000x = 2500

x = 2500/1000

x = 2.5 litres.

Therefore, the volume of the petrol in the can in litres is 2.5.

7 0

3 years ago

ANSWER = BRAINLIEST PLEAASSEE

baherus [9]

1) Mass won't change ( $59$ kg).

2) $W_{TM}=mg_{_{TM}}\medskip\\m=\dfrac{W_{TM}}{g_{_{TM}}}\medskip\\W_{E}=mg_{_E}=W_{TM}\dfrac{g_{_E}}{g_{_{TM}}}=20\times \dfrac{9.08}{1.62}\approx 112.0988$

3) $W_{TM}=mg_{_{TM}}=100\times 1.62=162$

4) $mg_{_{object}}=G\dfrac{M_{object}m}{r^2}\medskip\\g_{_{object}}=G\dfrac{M_{object}}{r^2}$

As $G$ and $r$ are constants, $g_{_{object}}\propto M_{object}$ . In other words, the more massive the object is, the bigger its gravitational acceleration (obviously, the lighter the object is, the lesser its gravitational acceleration)

5 0

3 years ago

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