All categories

3 years ago

What types of alternative fuels did bp pursue after browne became ceo in 1995?

Physics

1 answer:

Sliva [168]3 years ago

8 0

Answer:solar energy

Explanation:

This is the energy gotten from sunlight to knock off electrons from fee atom.

This panel contains photovoltaic cells

You might be interested in

What is the object’s velocity, in meters per second, at time t = 2.9? Calculate the object’s acceleration, in meters per second

madreJ [45]

Answer:

the question is incomplete, below is the complete question

"An object is undergoing simple harmonic motion along the x-axis. Its position is described as a function of time by x(t) = 5.5 cos(4.4t - 1.8), where x is in meters, the time, t, is in seconds, and the argument of the cosine is in radians.

a.What is the object's velocity, in meters per second, at time t = 2.9?

b.Calculate the object's acceleration, in meters per second squared, at time t = 2.9.

c. What is the magnitude of the object's maximum acceleration, in meters per second squared?

d.What is the magnitude of the object's maximum velocity, in meters per second?"

a. $v(t)==24.1m/s$

b. $a(t)=3.79m/s^{2}$

c. $a_{max}=106.48m/s^{2}$

d. $v_{max}=24.2m/s$

Explanation:

the gneral expression for the displacement of object in simple harmonic motion is represented by

$x(t)=Acos(wt- \alpha)\\$

while the velocity is express as

$v(t)=-Awcos(4.4t-1.8)\\$

and the acceleration is

$a(t)=-aw^{2}cos(wt- \alpha )\\$

Note: the angle is in radians

The expression for the displacement from the question is $x(t)=5.5cos(4.4t-1.8)\\$

comparing, A=5.5, w=4.4,α=1.8

a.To determine the object velocity at t=2.9secs,

we substitute for t in the velocity equation

$v(t)=-5.5*4.4sin(4.4*2.9-1.8)\\v(t)=-24.2sin(10.96)\\$

$v(t)=-24.2*(-0.9993)\\v(t)==24.1m/s$

b.To determine the object acceleration at t=2.9secs,

we substitute for t in the acceleration equation

$a(t)=-5.5*4.4^{2} cos(4.4*2.9-1.8)\\a(t)=-106.48cos(10.96)\\$

$a(t)=-106.48*0.0356\\a(t)=3.79m/s^{2}$

c. The acceleration is maximum when the displacement equals the amplitude. hence magnitude of the object acceleration is

$a_{max}=-w^{2}A\\ a_{max}=-4.4^{2}*5.5\\ a_{max}=106.48m/s^{2}$

d.The maximum velocity is expressed as

$v_{max}=wA\\v_{max}=4.4*5.5\\v_{max}=24.2m/s$

5 0

3 years ago

What is the average density of a neutron star that has the same mass as the sun but a radius of only 20.0 km?

IrinaK [193]

Answer: $5.935(10)^{13}g/cm^{3}}$

Explanation:

Density is a characteristic property bodies and materials, and is defined as the relationship between the mass $m$ and the volume $V$ , as shown below: